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myrzilka [38]
3 years ago
9

The manager of a radio station decides that on each successive evening (7 days per week), a Beethoven piano sonata will be playe

d followed by a Beethoven symphony followed by a Beethoven piano concerto. For how many years could this policy be continued before exactly the same program would have to be repeated? (Assume there are 365 days in a year. Round your answer up to the nearest whole number.)
Mathematics
1 answer:
VashaNatasha [74]3 years ago
8 0

Answer:

3 years, 11 months and 10 days

Step-by-step explanation:

Beethoven wrote

32 piano sonatas

9 symphonies

5 piano concertos

By the fundamental principle of counting there are

32 times 9 times 5 ways of combining these pieces in the required order.

32 times 9 times 5 = 1,440

As there are 365 days in a year, the policy decided by the manager could be continued during

1,440/365 = 3.9452 years.

But 3.9452 years = 3 years + 0.9452 years.

As 1 year equals 12 months

0.9452 years = 11.3424 months

11.3424 months = 11 months+0.3424 months

As 1 month = 30 days

0.3424 months = 10.27 days = 10 days rounded to the nearest integer

So, the manager could continue this policy for

3 years, 11 months and 10 days without repeating the program.

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Determine whether the points lie on straight line.
wel

Answer:

A) Non-collinear- does not lies on straight line

B) Collinear- lie on straight line

Step-by-step explanation:

We have to check collinearity of three points.

The points (x_1, y_1, z_1),(x_2, y_2, z_2),(x_3, y_3, z_3) are said to be collinear if,

\left[\begin{array}{ccc}x_1&y_1&z_1\\x_2&y_2&z_2\\x_3&y_3&z_3\end{array}\right] = 0

A) A(2, 5, 3), B(3, 7, 1), C(1, 4, 4)

\left[\begin{array}{ccc}2&5&3\\3&7&1\\1&4&4\end{array}\right] \\\\=2(28-4)-5(12-1)+3(12-7)\\= 8 \neq 0

Thus, the given points are not collinear.

B) D(0,-5,5), E(1,-2,4), F(3,4,2)

\left[\begin{array}{ccc}0&-5&5\\1&-2&4\\3&4&2\end{array}\right] \\\\=0(-4-16)+5(2-12)+5(4+6)\\=0

Thus, the given points are collinear.

6 0
3 years ago
A bicycle is now selling for $315 it was discounted by 60 percent. What was the original cost.
Dovator [93]
189$
jfisiufjskei ieidudhek
3 0
4 years ago
Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
Identify the vertex and the axis of symmetry of the graph of the function y=3(x+2)2-3
dedylja [7]
Axis -b/2a=-12/2*3=-2
vertex(-2,-3)
8 0
4 years ago
1. Describe the relationship between the terms in the sequence 13, 26, 52,
Vilka [71]

Answer: All of the numbers in the sequence are going up twice the amount as before. The next three terms will be 208, 416, 832

4 0
3 years ago
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