In a given figure if o is the centre of circle and oabc is a parallelogram find the value of abc
1 answer:
From the given information, we get the value of ABC = 120°.
<h3>How to estimate the value of ABC?</h3>
Given: In the figure, O exists the center of the circle and OABC exists as a parallelogram.
Now, the radius of the circle exists
OA = OB = OC
Opposite sides of a parallelogram are equal
AB = OC and OA = BC
In ∆OAB,
OA = OB = AB and,
In ∆OCB,
OC = OB = BC
Therefore, ∆OAB and ∆OCB exist in equilateral triangles.
All angles of an equilateral triangle are equivalent to 60°.
Hence, ∠ABC = ∠OBA + ∠OBC
∠ABC = 60° + 60°
∠ABC = 120°
Therefore, the value of ∠ABC = 120°.
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The function represents a reflection of
across the y-axis ⇒ 3rd answer
Step-by-step explanation:
Let us revise the reflection across the axes
- If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)
- If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)
∵
∵ g(x) is the image of f(x) after reflection across the y-axis
- From the rule above reflection across the y-axis changes the sign of x
∴
∵
∵
∴
∴
The function represents a reflection of
across the y-axis
Learn more:
You can learn more about reflection in brainly.com/question/5017530
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