Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
We know that
X²+y²=9 -------> X²+y²=3²
is the equation of a circle with center (0,0) and radius r=3 units
so
<span>the translation of four units to the right and three units down is equals to move the center (0,0)--------> (0+4,0-3)------> (4.-3)
the new center of the circle is (4,-3)
the new equation is
(x-4)</span>²+(y+3)²=3²
see the attached figure
Answer:
1. 94.25 is the surface area, 94.25 to 56.55 is the ratio of surface area to volume
2.138.23 is the surface area 138.23 to 113.1 is the ratio of surface area to volume
Answer:
Step-by-step explanation:
I attached the graphs