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3 years ago

Please help ASAP 10 points

Mathematics

2 answers:

Olin [163]3 years ago

6 0

Answer:

Step-by-step explanation:

This is the greatest integer function. [x] is the biggest integer that is less or equal than x so [-4.6] is -5.

dimulka [17.4K]3 years ago

3 0

Answer:-4

Step-by-step explanation:

Read more on functions;

brainly.com/question/10439235

6 0

3 years ago

Read 2 more answers

Chris paid $36 for 3 tanktops and 2 shirts. a shirt cost 3 times as much as a tank top. how much did chris pay for the 2 shirts?

devlian [24]

Answer:

$72

Step-by-step explanation:

36/3=12

1 tanktop=$12

12*3=36

1 shirt equals=$36

36*2=72

2 shirts=$72

4 0

3 years ago

The sale price of a table is $472 it was 20% off what was the original price?

ira [324]

To solve, set an equation:

472=0.8x

Divide both sides by 0.8

472/0.8=0.8x/0.8

x=590

Answer: The original price was $590

5 0

3 years ago

Which equation describes the same line as y- 6 = -4(x + 1)?

BARSIC [14]

The answers to the question is A.

7 0

3 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is:

$(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})$

$(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]$

$(x,y) = (10.452, 34.531)\,[km]$

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

$\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}$

$\theta \approx 16.840^{\circ}$

And the distance from the camp is calculated by the Pythagorean Theorem:

$r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}$

$r = 36.078\,km$

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0

3 years ago