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3 years ago

I need help with number 2 please.

Mathematics

2 answers:

Finger [1]3 years ago

7 0

The answer is 73.3333333

zalisa [80]3 years ago

5 0

The answer is 73.3333333 ounces<span>
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A triangle having sides of 2, 2, and 3 contains _____.

nikdorinn [45]

Don't quote me but i'm pretty sure it is a right triangle

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3 years ago

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What is the value of x

borishaifa [10]

$x^2=4^2+4^2\\
x^2=2\cdot16\\
x^2=32\\
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3 years ago

A restaurant has 50 tables. 40% of the tables have 2 chairs at each table. The remaining 60% of the tables have 4 chairs at each

liubo4ka [24]

Answer:

Total number of chairs in the restaurant = 160.

Step-by-step explanation:

Total number of tables in the restaurant = 50

It is given that 40% of the tables have 2 chairs at each table.

40% of 50 = $\frac{40}{100} (50)$

= 20

So, 20 tables have 2 chairs at each table.

Number of chairs required for 20 tables = 20 × 2 = 40

Remaining 60% of the tables have 4 chairs at each table.

60% of 50 = $\frac{60}{100} (50)$

= 30

So, 30 tables have 4 chairs at each table.

Number of chairs required for 30 tables = 30 × 4 = 120

Hence, total number of chairs in the restaurant = 40 + 120 = 160.

5 0

3 years ago

Help please i don’t know how to do it

Norma-Jean [14]

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\$

From the initial condition,

$\ln|3-1|=\frac{0^{3}}{3}+C\\\ln 2=C$

So we have that $\ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1$

4 0

2 years ago

This was given to me during a summative test and the teacher didn't bother giving me the correction. I just cannot figure it out

Dmitry [639]

Base be y

ATQ

$\\ \sf\longmapsto xy=6050\dots 1$

$\\ \sf\longmapsto 2(x+y)=220\implies x+y=110\dots 2$

Now

$\\ \sf\longmapsto (x+y)^2=x^2+y^2+2xy$

$\\ \sf\longmapsto 110^2-2(6050)=x^2+y^2$

$\\ \sf\longmapsto 12100-12100=x^2+y^2$

$\\ \sf\longmapsto x^2+y^2=0\dots(3)$

From all equations

$\\ \sf\longmapsto (x-y)^2=x^2+y^2-2xy$

$\\ \sf\longmapsto (x-y)^2=0-2(6050)$

$\\ \sf\longmapsto (x-y)^2=-12100$

$\\ \sf\longmapsto (x-y)=110\dots(4)$

Now

Adding 3 and 4

$\\ \sf\longmapsto 2x=220$

$\\ \sf\longmapsto x=110m$

One side won't be covered hence

y=2(110)=220m

7 0

2 years ago

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