To determine the amount of oxygen that is present in the compound, we have to assume that the given compound contains carbon, hydrogen and oxygen only or else we will not be able to determine the answer. We need to convert the moles of the elements given to units of grams by using the atomic mass of these elements. Then, from the total amount of the compound we subtract the masses of the elements. We do as follows:
mass
0.117 mol C ( 12.01 g / 1 mol ) = 1.41 g
0.233 mol H ( 1.01 g / 1 mol ) = 0.24 g
Mass O = 3.50 g - 1.41 g - 0.24 g = 1.85 g O
Moles O = 1.85 g O ( 1 mol / 16 g ) = 0.116 moles O
apparently it’s saline water.
Answer: Lithium
Explanation: The balanced chemical equation is:
It can be seen, 4 moles of lithium combines with 1 mole of oxygen gas to produce 2 moles of lithium oxide.
Thus 8.4 moles of lithium combines with=of oxygen gas to produce 4.2 moles of lithium oxide.
As, Lithium limits the formation of product, it is the limiting reagent and Oxygen gas is present in excess, it is called the excess reagent. (4.6-2.1)=2.5 moles of oxygen gas are present in excess.
Answer:
Volume of the calcium hydroxide solution used is 0.0235 mL.
Explanation:
Moles of KHP =
According to reaction, 2 moles of KHP with 1 mole of calcium hydroxide , then 0.0330 moles of KHP will recat with ;
of calcium hydroxide
Molarity of the calcium hydroxide solution = 0.703 M
Volume of calcium hydroxide solution = V
Volume of the calcium hydroxide solution used is 0.0235 mL.
The engine displacement in cubic nanometer (nm³) is 8.785×10²⁴ nm³
<h3>Data obtained from the question </h3>
- Displacement in in³ = 536 in³
- Displacement in nm³ =?
<h3>Conversion scale </h3>
1 in³ = 1.639×10²² nm³
With the above convesion scale we can obtain the displacement in nm³
<h3>How to determine the displacement in nm³</h3>
1 in³ = 1.639×10²² nm³
Therefore,
536 in³ = 536 × 1.639×10²²
536 in³ = 8.785×10²⁴ nm³
Thus, the displacement in nm³ is 8.785×10²⁴ nm³
Learn more about conversion:
brainly.com/question/2139943