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Masteriza [31]
3 years ago
13

Help me ASAP !!!!!!!!!!!!!!!

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

l, ll, lll, v

Explanation:

I just took the test ;)

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Which reaction type is the following: AgF + CaCl2 --> AgCl + CaF2
nevsk [136]

Explanation:

{\small{\underline{\bf{\red{answer...}}}}} \\  \\

\small\mathfrak\purple{Double  \: displacement \:  reaction} \\  \\ \small\mathfrak\orange{hope \: it \: helps...}

6 0
3 years ago
Explain why a propane torch is lit inside a hot air balloon during preflight preparations. Which gas law applies?
Olegator [25]

Propane torch is lit inside a hot air balloon during pre-flight preparation because the heat from the touch is needed to heat the cold air inside the balloon, so that the air will expand and become less dense and rise, thus providing a lift for the balloon. This is line with charle's law, which states that, the volume of a fixed mass of ideal gas is directly proportional to the absolute temperature. This law implies that, as the temperature of the air inside the balloon increase, the volume of the balloon also increases.

5 0
3 years ago
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WILL GIVE OUT BRAINLY
Margarita [4]

Answer:

3. An oxygen atom with 8 electrons, 8 protons, and 9 neutrons .

Explanation:

if an atom contains equal numbers of protons and electrons, the atom is described as being neutral.

4 0
3 years ago
How much of a 0.250 M lithium hydroxide is required to neutralize 20.0 mL of 0.345M chlorous acid?
Bumek [7]

Answer:

27.6mL of LiOH 0.250M

Explanation:

The reaction of lithium hydroxide (LiOH) with chlorous acid (HClO₂) is:

LiOH + HClO₂ → LiClO₂ + H₂O

<em>That means, 1 mole of hydroxide reacts per mole of acid</em>

Moles of  20.0 mL = 0.0200L of 0.345M chlorous acid are:

0.0200L ₓ (0.345mol / L) = <em>6.90x10⁻³ moles of HClO₂</em>

To neutralize this acid, you need to add the same number of moles of LiOH, that is 6.90x10⁻³ moles. As the LiOH contains 0.250 moles / L:

6.90x10⁻³ moles ₓ (1L / 0.250mol) = 0.0276L of LiOH =

<h3>27.6mL of LiOH 0.250M</h3>
6 0
3 years ago
For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts.
Anton [14]

Answer:-  2.4 mol NO_2 .

Solution:- It asks to calculate the moles of NO_2 formed when 1.2 moles of N_2O_5 are reacted.

There is 2:4 mol ratio between N_2O_5 and NO_2 . So, the moles of reactant are multiplied by the mol ratio to get the moles of NO_2 . The calculations are shown below:

1.2mol N_2O_5(\frac{4mol NO_2}{2mol N_2O_5})

= 2.4 mol NO_2

So, 2.4 moles of NO_2 are formed when 1.2 moles of  N_2O_5 were reacted.

7 0
3 years ago
Read 2 more answers
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