The pressure of the tyre after the temperature change is 0.89atm. Details about pressure can be found below.
<h3>How to calculate pressure?</h3>
The pressure of the tyre can be calculated using the following equation:
P1/T1 = P2/T2
Where;
- P1 = initial pressure
- P2 = final pressure
- T1 = initial temperature
- T2 = final temperature
According to this question, a tyre at 21°C (294K) has a pressure of 0.82 atm. Its temperature decreases to –3.5°C (269.5K).
0.82 × 294 = P2 × 269.5
241.08 = 269.5P2
P2 = 241.08 ÷ 269.5
P2 = 0.895atm
Therefore, the pressure of the tyre after the temperature change is 0.89atm.
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Answer:
chemistry, deposition occurs when molecules settle out of a solution. Deposition can be viewed as a reverse process to dissolution or particle re-entrainment. It is a phase change from the gaseous state to a solid, without passing through the liquid state, also called re-sublimation.
Explanation:
Examples include beaches, deltas, glacial moraines, sand dunes and salt domes. In severely cold temperatures frost will form on windows because the water vapor in the air comes into contact with a window and immediately forms ice without ever forming liquid water.
Answer:
B
Explanation:
equilibrium happens when two things are in complete balance and thermal is in reference to heat so two things are in thermal equilibrium once they have the same temperature.
Answer:
The heat produced is -15,1kJ
Explanation:
For the reaction:
2SO₂+O₂ → 2SO₃
The enthalpy of reaction is:
ΔHr = 2ΔHf SO₃ - 2ΔHf SO₂
As ΔHf SO₃ = -395,7kJ and ΔHf SO₂ = -296,8kJ
<em>ΔHr = -197,8kJ</em>
Using n=PV/RT, the moles of reaction are:
= <em>0,153 moles of reaction</em>
As 2 moles of reaction produce -197,8kJ of heat, 0,153moles produce:
0,153mol×
= <em>-15,1kJ</em>
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I hope it helps!
Answer:
The spin of the complex is 5.92 B.M
Explanation:
Please see the attachments below
