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4 years ago

HELP

Mathematics

1 answer:

vaieri [72.5K]4 years ago

3 0

4/8 simplified is 2/4 i think

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What is the total cost of troys order? PLEASE HELP ME WITH THIS QUESTION :0

jonny [76]

The answer is $93.75 because $3.15 times 8 equals $25.20. Then, $1.85 times 15 equals $27.75. And finally, $3.40 times 12 equals $40.80! Your final step would be to add them all together, which equals $93.75. Therefore,

Your final answer is $93.75.

8 0

4 years ago

What is g(x)? A. g(x) = -x B. g(x) = -2 C. g(x) = -1 D. g(x) = x²

tamaranim1 [39]

Answer:

C. g(x) = -|x|

Step-by-step explanation:

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3 years ago

Two samples were taken of fish caught on Small Lake and are shown in the table below. It is estimated that the Sm

kolezko [41]

Answer:

its 80 on edg

Step-by-step explanation:

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3 years ago

Find the measure of the missing angle. 77°

Georgia [21]

Answer: The missing angle is 13°

Step-by-step explanation:

Let ∠B

be the missing angle.

Let ∠A

be the angle that measures

77∘Let ∠C

the right angle that measures

90∘

The following is true of all triangles:

∠A+∠B+∠C=180∘

Express the above equation as

∠B

in terms of the other angles:

∠B=180∘−∠A−∠C

Substitute the values for ∠A and ∠C

∠B=180∘−77∘−90∘

∠B=13∘

4 0

3 years ago

APPLICATIONS

n200080 [17]

Answer:

(a) (4,9), (8,14).; (b) 1.25 in/h; (c) d = 1.25h + 4 ; (d) 4 in; (e) 19 in

Step-by-step explanation:

(a) Information as coordinate pairs

4 h, 9 in ⟶ (4, 9)

8 h, 14 in ⟶ (8,14)

The coordinates of the two points are (4,9), (8,14).

(b) Slope of the line

$\begin{array}{rcl}m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\ & = & \dfrac{14 - 9}{8 - 4}\\\\& = & \dfrac{5}{4}\\\\& = & \mathbf{1.25}\end{array}$

The slope of the line is 1.25 in/h

(c) Equation of the line

$\begin{array}{rcl}d & = & mh + b\\9 & = & \dfrac{5}{4} \times 4 + b\\\\9& = & 5 + b\\b & = & \mathbf{4}\\\end{array}$

The y intercept is at (0,4)

d = 1.25h + 4

(d) Depth when snowfall began

$\begin{array}{rcl}d &= &\text{0 h } \times \dfrac{\text{1.25 in}}{\text{1 h}} \text{+ 4 in}\\\\&= &\text{0 in+ 4 in}\\& = & \textbf{4 in}\\\end{array}$

The depth was 4 in when the snowfall began.

(e) Depth after 12 h

$\begin{array}{rcl}d &= &\text{12 h } \times \dfrac{\text{1.25 in}}{\text{1h}} \text{+ 4 in}\\\\&= &\text{15 in+ 4 in}\\& = & \textbf{19 in}\\\end{array}$

The depth would be 19 in after 12 h.

The figure below is a graph of your function. It shows that the depth was 4 in at the start of the snowfall, that it increases by 5 in every 4 h, and predicts a depth of 19 in after 12 h.

8 0

3 years ago