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3 years ago

Atul, Bryony and Charlotte share an amount of money in the ratio 4:11:10

Mathematics

1 answer:

Alchen [17]3 years ago

8 0

4 + 11 + 10 = 25.

Assuming Bryony is the middle number, she gets 11/25 fraction of the money.

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Please Help. Find the area. Thank you

Andru [333]

Answer:

432 yd squared

Step-by-step explanation:

This is a parallelogram. The area of a parallelogram is denoted by: A = bh, where b is the base and h is the height. Here, the base is b = 19 1/5 and the height is h = 22 1/2. Plug these in:

A = bh = (19 1/5) * (22 1/2)

To make this simpler, let's convert the numbers into decimals. 1/5 is just 0.2 so 19 1/5 is 19.2. 1/2 is just 0.5, so 22 1/2 is 22.5. Now we have:

A = 19.2 * 22.5 = 432

Thus the area is 432 yd squared.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Jayce looks around at an assembly. He notices his younger sister to his right and his older brother 48 feet ahead of him. If Jay

olganol [36]

Answer:

I think it's 50

Step-by-step explanation:

50 8s inbetween the two

6 0

3 years ago

Find the sum. (−a^3+4a−3)+(5a^3−a)

aev [14]

Answer:

4a³+3a-3

Step-by-step explanation:

You can solve this by combining like terms. Add the numbers with the correct exponents together.

-a³+5a³

4a-a

Thus, the answer is

4a³+3a-3

5 0

3 years ago

¿como se lee estos decimales 149,5652173913. ?

lesya [120]

shbsjdbdidbskbdkajsnsnbsbssv

3 0

3 years ago

Read 2 more answers

The production department has installed a new spray machine to paint automobile doors. As is common with most spray guns, unsigh

marta [7]

Answer:

10000*0.6065=6065

A. about 6,065

Step-by-step explanation:

Definitions and concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

$P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}$

And the parameter $\lambda$ represent the average ocurrence rate per unit of time.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda=0.5$ , $Var(X)=\lambda=0.5$ , $Sd(X)=707$

Solution to the problem

We want "how many would have no blemishes" so first we need to find the probability that X=0, since X represent on this case the number of blemishes on each door. And if we use the mass function we got this:

$P(X=0) =0.5^0 \frac{e^{-0.5}}{0!}=0.6065$

And now since we have a total of 10000 doors painted we can find how many we would expect with no blemishes:

10000*0.6065=6065

A. about 6,065

4 0

4 years ago