Answer: A)
x = # of students in math class
2x+7=40
B)
2x+7=40
-7
------------
2x = 33
--- ---
2 2
x = 76 students
The number (answer) is 2592.
Check your answer:
(substitute the numbers to see if they will equal 2592: <span>2^5 is 32 and 9^2 is 81)</span><span>
Now subsitute it into A^B*C^D: 32*81 is 2592.</span>
D. Rigid transformations were applied therefore not changing any of the shapes values.
First, an introduction: If the equation of the circle were x^2 + y^2 = 144, then the center would be at (0,0) and the radius would be 12. Note that the distance from the center to P(10,10) is 10sqrt(2), or 14.14. Thus, in this example, P would be OUTSIDE the circle (since 14.14 is greater than the radius 12).
Now let's focus on <span>(x-1)^2 + (y-2)^2 =144. Let x = 12 as an example; find the corresponding y: 9^2 + (y-2)^2 = 144, or (y-2)^2 = 63, and so y-2 is approx. -8 or +8. Then y (for x = 12) is either approx. -10 or 6: (12,-10) or (12,6). Are these inside the circle or outside?
A better way to address this would be as follows:
Find the distance from the center (1, 2) to the point P(10,10). If this distance is less than 12, the point P is inside C; if greater than 12, P is outside C.
This distance is sqrt( (10-2)^2 + (10-1)^2 ), or sqrt (64+81) = sqrt(145).
This is LARGER than sqrt(144). Thus, P is OUTSIDE the circle C.</span>
Answer:
(- 1, - 3 )
Step-by-step explanation:
the coordinates of the midpoint are the average of the coordinates of the endpoints, then
midpoint = (
, 
) = ( 
, 
) = (- 1, - 3 )
