mechanic #1's rate = x
mechanic #2's rate = y
* Their rate is dollars per hour ($/hr)
mechanic #1 worked for 20 hours (hr × $/hr = $)
20x = money earned by mech#1
and mechanic #2 worked for 5 hours
5y = money earned by mech#2
together they charged a total of $1150. So the amount of money earned by both mechanics.
20x + 5y = 1150
the sum of the two rates was $95 per hour.
x + y = 95
which means
x = 95 - y
plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.
20(95 - y) + 5y = 1150
solve for y
1900 - 20y + 5y = 1150
1900 - 15y = 1150
-15y = 1150 - 1900
-15y = -750
y = -750/-15
y = 50 $/hr
Now use this to solve for x
x + y = 95
x + 50 = 95
x = 95 - 50
x = 45 $/hr
mech#1 charged 45$/hr
mech #2 charged 50$/hr
Answer:
a = 2; b = -1; and c = 3
Step-by-step explanation:
Please see attached image for the step by step answer
Step-by-step explanation:
the number line : a potentially infinite horizontal line.
it shows all numbers, with 0 in the center, eher we are looking at it. the negative numbers go to the left of 0, with -1, -2, -3, ... going from right to left.
the positive numbers go to the right of 0, with 1, 2, 3 going from left to right.
point S = -14
and the distance to a point R (RS) is 10.
now, on such a line we can always go in 2 directions : left and right.
our starting point is S (-14).
going 10 units to the right (positive direction) we get to -4.
as -14 + 10 = -4
going 10 units to the left (negative direction) we get to -24.
as -14 - 10 = -24
so, R can be at -4 or -24.
They are called invertebrats
Answer:
A number line going from 0 to 3. An open circle is at 2. Everything to the left of the circle is shaded.
Step-by-step explanation:
First, remember that when an endpoint is not in the solution set, we graph an open circle. While if the endpoint is in the solution set, we graph it with a closed circle.
For example, in:
x > 2
x = 2 is not a solution, then we will have an open circle at x = 2
While in the case of:
x ≥ 2
x = 2 is a possible solution, then we graph with a closed circle.
Ok, in this case we have:
t < 2
t is strictly smaller than 2, and t = 2 is not a solution.
Then:
we will have an open circle at 2, and we need to shade all the values to the left of 2 (the values smaller than 2)
The correct option is:
A number line going from 0 to 3. An open circle is at 2. Everything to the left of the circle is shaded.
