For f(x)=x^2,sketch the graph of g(x)=f(-5x+10)
1 answer:
The graph of g(x) = f(-5x+10) is given in the figure.
<h3>What is a graph?</h3>A diagram showing the relation between two variable quantities,each measured along one of a pair of axes at right angles.
It is given that f(x) = x^2
and g(x ) = f(-5x+10)
Now putting the value of f(x) in g(x) we get,
g(x) = f(-5x+10) = (-5x+10)^2
So, g(x) = (-5x+10)^2
now, making the table for g(x),
<u><em>x </em></u><u>g(x)</u>
0 100
1 81
2 0
3 25
4 100
5 225
Hence,the graph of g(x) = f(-5x+10) is given in the figure.
More about graph :
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Answer:
- sin = -√3/2
- cos = -1/2
- tan = √3
- sec = -2
- csc = (-2/3)√3
- cot = (√3)/3
Step-by-step explanation:
See the attached picture for a drawing of the angle and its terminal point coordinates. Those are (cos(4π/3), sin(4π/3)), so we have the following trig function values:
sin(4π/3) = -√3/2
cos(4π/3) = -1/2
tan(4π/3) = sin/cos = √3
sec(4π/3) = 1/cos = -2
csc(4π/3) = 1/sin = -(2√3)/3
cot(4π/3) = 1/tan = (√3)/3
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<em>Additional comment</em>
It helps to know that 1/√a = (√a)/a. This lets you write the ratios with a rational denominator in each case.
