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insens350 [35]
3 years ago
6

Find the sum: 6/x-4+5/x

Mathematics
2 answers:
Alchen [17]3 years ago
7 0
<span>6/x-4+5/x     u can make common denominator
</span>
6 / x - 4 x /  x  + 5 /x 

the answer is 11/x -  4x / x  
<span> </span>
Bas_tet [7]3 years ago
4 0

The answer from the choices would be 11x-20/x^2-4x the last option D. Just took the practice on edg.

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Which of the following sequences are not geometric? (check all that apply) a. 2,10,50,250,1250 b. 1,4,9,16,25,36 c. -4,-2,-1,-0.
Romashka [77]
A is geometric because each number is multiplied by 5.

B is not geometric because it is an arithmetic sequence. 

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D is neither geometric not arithmetic because there is no common ratio and there is not a pattern being added or subtracted to each number.

So, your answer should be B and D.
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3 years ago
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ohaa [14]
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3 0
2 years ago
Rewrite the expression using the distributive property <br><br> 2(4 + X)
Novosadov [1.4K]

Answer:

2(4 + X)

2*4 + 2*X

8+2X

thank you

Step-by-step explanation:

hope my answer is helpful to you

3 0
3 years ago
Read 2 more answers
Please help due ASAP <br> I really need help
elena55 [62]
C because it is icoceles.
6 0
3 years ago
Read 2 more answers
How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x​
ivanzaharov [21]

\Large \mathbb{SOLUTION:}

\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes}  \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}

5 0
3 years ago
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