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Ivenika [448]
2 years ago
14

F(x)=ax+b/2 then f^-1 (x-1) =2x-5/2 find a and b​

Mathematics
1 answer:
krok68 [10]2 years ago
8 0

From the given inverse function, we have

f^{-1}(x-1) = 2x - \dfrac52 \\\\ \implies f^{-1}(x) = f^{-1}((x+1)-1) = 2(x+1) - \dfrac52 = 2x-\dfrac12

By definition of inverse function,

f\left(f^{-1}(x)\right) = x

so that

f\left(2x-\dfrac12\right) = x

a\left(2x-\dfrac12\right) + \dfrac b2 = x

2ax - \dfrac a2 + \dfrac b2 = x

\implies\begin{cases}2a=1 \\\\ -\dfrac a2+\dfrac b2 = 0\end{cases}

\implies \boxed{a=\dfrac12}

\implies \dfrac b2 = \dfrac a2 \implies \boxed{b=\dfrac12}

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The missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

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We have the roots of a quadratic equation:

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To find the quadratic equation:

(x - (5+3i))(x - (5-3i))

\rm =x^2+x\left(-\left(5-3i\right)\right)-\left(5+3i\right)x-\left(5+3i\right)\left(-\left(5-3i\right)\right)

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The quadratic equation is:

= x² -10x + 34

Thus, the missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.

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