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lukranit [14]
1 year ago
12

You are choosing between two plans at a discount warehouse. Plan A offers an annual membership fee of ​$30 and you pay 90​% of t

he​ manufacturer's recommended list price. Plan B offers an annual membership fee of ​$90 and you pay 70​% of the​ manufacturer's recommended list price. How many dollars of merchandise would you have to purchase in a year to pay the same amount under both​ plans? What will be the cost for each​ plan?
Mathematics
1 answer:
docker41 [41]1 year ago
4 0

The cost for plan A and plan B at a discount warehouse is $57 and $153 respectively.

<h3>Equation</h3>

Plan A:

  • Membership fee = $30

Manufacturer's recommended list price = 90%

= 90% × 30

= 0.9 × 30

= $27

Total cost of plan A = $30 + $27

= $57

Plan B:

  • Membership fee = $90

Manufacturer's recommended list price = 70%

= 70% × 90

= 0.7 × 90

= $63

Total cost of plan B = $90 + $63

= $153

Therefore, the cost for plan A and plan B at a discount warehouse is $57 and $153 respectively.

Learn more about equation:

brainly.com/question/2972832

#SPJ1

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Answer:

cost of tacos=$2

cost of soda=$1

Step-by-step explanation:

x=price of tacos

y=price of soda

3x+y=7 --> y=7-3x

4x+2y=10 --> y=5-2x

5-2x=7-3x

x=2

y=5-2(2)=1

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3 years ago
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UkoKoshka [18]

Answer:

3/26

Step-by-step explanation:

Probability of the first box to have the secret decoder ring is 18 out of 52:

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Probability of the second box to have the ring is 17 out of 51, because one box with the ring already selected and not counted:

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Probability that both of them have the secret decoder ring:

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<u>So the answer is</u> 3/26

4 0
3 years ago
Anyone know the answer to all of them added together
Evgesh-ka [11]

Answer:

13x + 14

Step-by-step explanation:

5x + 6 + 3x = 8x + 6.

8x + 6 + x + 1 + x + 1 + 2= 10x + 10

10x + 10 + (2²)(i think) = 10x + 14

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final answer

3 0
2 years ago
Read 2 more answers
To rent a certain meeting room, a college charges a reservation fee of $15 and an additional fee of $6 per hour. The chemistry c
Dafna1 [17]

Answer:

To spend at most $93, they need to rent the room less than or equal 13 hours.

Step-by-step explanation:

<u><em>The complete question is</em></u>

To rent a certain meeting room, a college charges a reservation fee of $15 and an additional fee of $6 per hour. The chemistry club wants to spend at most $93 on renting a room. What are the possible numbers of hours the chemistry club could rent the meeting room? Use t for the number of hours. Write your answer as an inequality solved for t,

Let

t ----> the number of hours

we know that

I this problem the word "at most" means "less than or equal to"

The number of hours rented multiplied by the cost per hour, plus the reservation fee, must be less than or equal to $93

so

The inequality that represent this situation is

6t+15\leq 93

solve for t

subtract 15 both sides

6t\leq 93-15

6t\leq 78

Divide by 6 both sides

t\leq 13\ hours

therefore

To spend at most $93, they need to rent the room less than or equal 13 hours.

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Answer:15 times

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For the 3 batches it is 3 x 5/4 (5/4 is how much each batch costs)=15/4

And you must divide 15/4 by 1/4 or multiply it by 4 crossing out the denominator giving you your answer 15

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