Anyone knows the answer ?

Need help FAST please NO LINKS!!!! Mark BRAINLLEST to whoever gets it right

olga nikolaevna [1]

Answer:

x=24

Step-by-step explanation:

Because the triangle is a 30-60-90 triangle, you can find side x, the hypotenuse, by doubling the short side 12. Therefore, x=2(12)=24.

7 0

3 years ago

Two circles of radius 1 are centered at $(4,0)$ and $(-4,0).$ How many circles are tangent to both of the given circles and also

galben [10]

Answer:

1 circle

Step-by-step explanation:

Given two circles (red circles on the diagram).

There are two tangent circles to both of the given circles (blue circles on the diagram), and only one of them is passing through the point (0,5).

Let's check it.

The equations of the tangent circles are

$x^2+y^2=9\ [\text{Smaller tangent circle}]\\ \\x^2+y^2=25\ [\text{Larger tangent circle}]$

Check whether point (0,5) lies on the smaller circle:

$0^2 +5^2 =0+25=25\neq 9$

No

Check whether point (0,5) lies on the larger circle:

$0^2 +5^2 =0+25=25$

Yes

Answer: 1 circle

7 0

3 years ago

Write a system of equations to represent this situation.

Morgarella [4.7K]

SH

3+2(x)=y

RaR

1+3(x)=y

5 0

3 years ago

Equivalent Expression

ELEN [110]

Answer:

B. 6x - 12y + 10x

Step-by-step explanation:

A: expression equals 10x - 12y, doesn't equal step 2

B: expression equals 16x - 12y, is the same as step 2

C: expression equals 16x - 30y, doesn't equal step 2

D: expression equals 25x - 30y, doesn't equal step 2

3 0

4 years ago

Please just (c)fog-¹

omeli [17]

f(x) = 1/(1 - x)

g(x) = (x - 1)/x

The inverse functions f ⁻¹(x) and g ⁻¹(x), if they exist, are such that

f( f ⁻¹(x) ) = x

g( g ⁻¹(x) ) = x

So we have

f( f ⁻¹(x) ) = 1/(1 - f ⁻¹(x) ) = x

Solve for f ⁻¹(x) :

1 = (1 - f ⁻¹(x) ) x

1 - f ⁻¹(x) = 1/x

f ⁻¹(x) = 1 - 1/x

f ⁻¹(x) = (x - 1)/x

and so f ⁻¹(x) = g(x).

Similarly, you can solve for g ⁻¹(x) :

g( g ⁻¹(x) ) = (g ⁻¹(x) - 1) / g ⁻¹(x) = x

1 - 1/g ⁻¹(x) = x

1/g ⁻¹(x) = 1 - x

g ⁻¹(x) = 1/(1 - x)

So we know f(x) and g(x) are inverses of one another,

f ⁻¹(x) = g(x)

g ⁻¹(x) = f(x)

Then

(a) (f o g)(x) = x

(b) (g o f ⁻¹)(x) = g(g(x)) = (g(x) - 1)/g(x) = 1 - 1/g(x) = 1 - x/(x - 1) = 1/(1 - x)

(c) (f o g ⁻¹)(x) = f(f(x)) = 1/(1 - f(x) ) = 1/(1 - 1/(1 - x)) = 1/(x/(x - 1)) = (x - 1)/x

8 0

3 years ago