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Molodets [167]
2 years ago
14

Quick algebra 1 question for 10 points!

Mathematics
2 answers:
nadezda [96]2 years ago
7 0

Answer:

C (Third option)

Step-by-step explanation:

The prime factorization of 675 is 5*5*3*3*3 or 5^2*3^3. With the square root, we take out all square integers, leaving (5*3)(sqrt3). The answer is 15(sqrt3) or C.

Anna [14]2 years ago
4 0
  • √675

Break

  • √225×3
  • √225√3
  • √15²√3
  • 15√3

Option C

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Circle X is shown. Points W, Y, and Z are on the circle. Lines are drawn through each point on the circle.
Dimas [21]

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Step-by-step explanation:

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6 0
4 years ago
Read 2 more answers
Give the following number in Base 16<br>NO LINKS!!! ​
olga nikolaevna [1]

Answer:

\large{\boxed{35_{10} = \sf 23_{16}}}

Explanation:

\sf Given : 35_{10}

Compute:

35 ÷ 16 = 2.1875 = 2R3

2 ÷ 16 = 0.125 = 0R2

Jot down the remainders:

  • 3        ↑
  • 2        ↑

======

\sf Answer :  \ 35_{10}   =  23_{16}

\hrulefill

Let's look at another example:  \sf 325_{10} = [?]_{16}

Compute:

325 ÷ 16 = 20.3125 = 20R5

20 ÷ 16 = 1.25 = 1R4

1 ÷ 16 = 0.0625 = 0R1

Jot down remainders:

  • 5        ↑
  • 4        ↑
  • 1         ↑

=====

\sf 325_{10} = [145]_{16}

\hrulefill

Another example: \sf 500_{10} = [?]_{15}

Compute:

500 ÷ 15 = 33.33... = 33R5

33 ÷ 15 = 2.2 = 2R3

2 ÷ 15 = 0.13... = 0R2

Jot down remainders:

  • 5      ↑
  • 3       ↑
  • 2       ↑

=====

\sf 500_{10} = [235]_{15}

7 0
2 years ago
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Effectus [21]
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8 0
3 years ago
94 passengers rode in a train from City A to City B. Tickets for regular coach seats cost ​115$. Tickets for sleeper cars seats
Kisachek [45]

Using a system of equations, it is found that 41 regular and 53 sleeper seat tickets were sold.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

  • Variable x: Regular coach seats.
  • Variable y: Sleeper cars seats.

94 passengers rode in a train from City A to City B, hence:

x + y = 94

Tickets for regular coach seats cost ​115$. Tickets for sleeper cars seats cost ​281$. The receipts for the trip totaled 19,608​$, hence:

115x + 281y = 19608

From the first equation, x = 94 - y, hence, replacing on the second.

115x + 281y = 19608

115(94 - y) + 281y = 19608

166y = 8798

y = \frac{8798}{166}

y = 53

x = 94 - y = 94 - 53 = 41

Hence, 41 regular and 53 sleeper seat tickets were sold.

To learn more about system of equations, you can take a look at brainly.com/question/14183076

5 0
2 years ago
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