Question

94 passengers rode in a train from City A to City B. Tickets for regular coach seats cost ​115$. Tickets for sleeper cars seats cost ​281$. The receipts for the trip totaled 19,608​$. How many passengers purchased each type of​ ticket?

Answer 1

Using a system of equations, it is found that 41 regular and 53 sleeper seat tickets were sold.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

• Variable x: Regular coach seats.

• Variable y: Sleeper cars seats.

94 passengers rode in a train from City A to City B, hence:

$x + y = 94$

Tickets for regular coach seats cost ​115$. Tickets for sleeper cars seats cost ​281$. The receipts for the trip totaled 19,608​$, hence:

$115x + 281y = 19608$

From the first equation, x = 94 - y, hence, replacing on the second.

$115x + 281y = 19608$

$115(94 - y) + 281y = 19608$

$166y = 8798$

$y = \frac{8798}{166}$

$y = 53$

$x = 94 - y = 94 - 53 = 41$

Hence, 41 regular and 53 sleeper seat tickets were sold.

To learn more about system of equations, you can take a look at brainly.com/question/14183076