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3 years ago

13

Only 5-8 It’s Probability

1 answer:

andrey2020 [161]3 years ago

3 0

For starters, the probability of finding any of these colors is a 50/50 type of thing, or in this case, an equal quarter. So each would be 1/4, or 25%. Unless, of course, they're lying about having one or more colors of marbles in their possession. But I'm answering under the assumption that they're not.

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Look for a Pattern Identify the coordinates of four points on the line with

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Answer:

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Hello how are you? Tell me in an answer for 100 points

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3 years ago

Read 2 more answers

Fuaad solved an absolute value inequality and expressed the solution as . What is another way to show Fuaad’s solution? For all

Ira Lisetskai [31]

Answer:

{x I - 12 < x < 7}

Step-by-step explanation:

Fuaad solved an absolute value inequality and expressed the solution as - 12 < x < 7.

So, the value of x lies between - 12 and 7 but not including - 12 and 7.

Option C will give another way to show Fuaad's solution.

It is {x I - 12 < x < 7}, which means x is a variable which belongs with in the interval (- 12, 7). (Answer)

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4 years ago

The points (7,r) and (8,9) fall on a line with a slope of 5. What is the value of r?

mrs_skeptik [129]

Answer:

r = 4

Step-by-step explanation:

Calculate the slope m using the slope formula and equate to 5

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (7, r ) and (x₂, y₂ ) = (8, 9)

m = $\frac{9-r}{8-7}$ = $\frac{9-r}{1}$ = 9 - r = 5 ( subtract 9 from both sides )

- r = - 4 ( multiply both sides by - 1 )

r = 4

7 0

4 years ago

Let a, b, c, and d be real numbers with a, c 6= 0. Prove that the lines y = ax+b and y = cx + d have the same x-intercept if and

Monica [59]

Step-by-step explanation:

We have got the lines :

$y=ax+b\\y=cx+d$

Both lines intercept the x-axis in the point :

$I = (i_{1} ,i_{2})$

In all point from x-axis the y-component is equal to 0.

$I=(i_{1},o)$

We replace the I point in the lines equations:

$0=a(i_{1})+b \\0=c(i_{1})+d$

From the first equation :

$0=a(i_{1})+b \\-b=a(i_{1})\\i_{1}=\frac{-b}{a}$

From the second equation :

$0=c(i_{1})+d\\ -d=c(i_{1})\\i_{1}=\frac{-d}{c}$

Then $i_{1}=i_{1}$

Finally :

$\frac{-b}{a}=\frac{-d}{c} \\\frac{b}{a}=\frac{d}{c} \\ad=bc$

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc

8 0

3 years ago