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1 year ago

A cat is lying on its abdomen with its limbs extended. The view of the tarsus in this position would be called quizlet

1 answer:

4 0

A cat is lying on its abdomen with its limbs extended. The view of the tarsus in this position would be called Plantarodorsal (PID.)

What is plantarodorsal?

The sole of the foot, also known as the plantar region, is the part of the foot that touches the ground.
The dorsum of the foot, also known as the dorsal region, is the part of the foot that faces upward.

What part of the foot is the dorsal?

The dorsum of foot is the area facing upwards while standing.

What is dorsal and plantar flexion?

Plantar flexion describes foot movement contracting muscles in the sole of the foot while its opposite motion, dorsal flexion or dorsiflexion, describes movement toward the upper side or back.

Learn more about plantarodorsal

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Energy stored in the bonds between an atom is called

d1i1m1o1n [39]

Chemical energy...................

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3 years ago

Why is it important to know a persons rhesus factor before an blood transfusion

Ronch [10]

Blood transfusion procedures, it is important to know the blood type of the receiver and the giver, since in cases of incompatibility can be blood clumping of the blood, which can lead to death.

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3 years ago

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What's another name for the shoulder blade

const2013 [10]

Answer:

Another name is Scapula

The bones of the shoulder consist of the humerus (the upper arm bone), the scapula (the shoulder blade), and the clavicle (the collar bone). The clavicle is the only bony attachment between the trunk and the upper limb. The familiar flat triangular bone at the back of the shoulder. Known familiarly as the wingbone or, medically, as the scapula. The word "scapula" (with the accent on the first syllable) is Latin.

Explanation:

Hope this helps :)

If I told too much the answer to your question is Scapula

8 0

3 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago

Which chromosomal defect is caused when part of a chromosome breaks off and reattaches backward on the same chromosome?

alisha [4.7K]

Answer:

Translocation

Explanation:

Translocation is a chromosomal defect in which part of a chromosome breaks off and reattaches backward on the same chromosome.

Translocation can happen due to many reasons like:

A) Some of the changes that arise around the time of conception or production of sperm or egg.

B) The inheritance of altered chromosome from father or mother.

Translocations can be divided into two forms:

Reciprocal translocation
Robertsonian translocation.

In reciprocal translocations, fragments of two chromosomes break off from two different places, break and swap each other's segments. While in Robertsonian translocation one chromosome attached with other.

Hope it help!

5 0

3 years ago

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