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1 year ago

An agricultural company called Phatsima Pty. Ltd. owns an rectangular fuel tank that measures 75 cm by 65 cm by 30 cm.

1 answer:

3 0

I believe that A is the answer. We can solve this by multiplying 75cm, 65cm and 30cm together. This would give us 146,250.00ml. We can then divide 146,250.00 by 1000 to receive 146.25. We then divide 146.25 by 2 to calculate how many litres there are in half a tank. This would result in 73.125. After that, we multiple 73.125 by the cost of the fuel, which is R20.35. We then receive R 1,480.09375, which can be rounded to R 1,480.10

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Find the area of the trapezoid.

UkoKoshka [18]

The answer is 68cm^2. Hope this helps!

4 0

2 years ago

Two mechanics worked on a car. The first mechanic worked for

Temka [501]

Write a system of equations:

x + y = 125

20x + 15y = 2100

Solving:

x = 125 - y

20(125 - y) + 15y = 2100
2500 - 20y + 15y = 2100
2500 - 5y = 2100
-5y = 2100 - 2500
-5y = -400
y=80

x + 80 = 125
x = 125 - 80
x = 45

The first charges 45$ per hour and the second charges 80$ per hour

4 0

2 years ago

What's the answer to: ‎X + 9 = 18 - 2x?

ser-zykov [4K]

Remember you can do anything to an equation as long as you do it to both sides

x+9=18-2x
add 2x to both sides
2x+x+9=18+2x-2x
3x+9=18+0
3x+9=18
minus 9 both sides
3x+9-9=18-9
3x+0=9
3x=9
divide both sides by 3
(3x)/3=9/3
(3/3)x=3
1x=3
x=3

4 0

3 years ago

Please answer fast The vertices of a rectangle are located at the coordinates (1, 4), (1, 5), (6, 5),

hammer [34]

Answer:

See below ~

Step-by-step explanation:

Drawing the rectangle (Refer attachment)

Horizontal sides

There are two x-values present : 1 and 6
Find the difference
6 - 1 = 5
The horizontal sides of the rectangle are 5 units long

Vertical sides

Two y-values are present : 4 and 5
Find the difference
5 - 4 = 1
The vertical sides of the rectangle are 1 unit long

Perimeter

2(Horizontal side + Vertical side)
2(5 + 1)
2(6)
12
The perimeter of the rectangle is 12 units

3 0

2 years ago

Which graph shows the solution to the system of linear inequalities? y< 2x-5 y>-3x + 1

trapecia [35]

Answer:

See explanation

Step-by-step explanation:

Plot the solution sets to both inequalities.

1. For the inequality $y$ First, plot the dotted line $y=2x+5$ (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

$2\cdot 0-5=-5$

so the origin does not belong to the needed part. Shade the part, which does not include origin.

2. For the inequality $y>-3x+1.$ First, plot the dotted line $y=-3x+1$ (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

$-3\cdot 0+1=1>0$

so the origin does not belong to the needed part. Shade the part, which does not include origin.

3. Find the common region of these two shaded parts - this is the solution to the system of two inequalities.

5 0

3 years ago