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sergij07 [2.7K]
3 years ago
7

Why might where you live be a factor in determining your utility costs?

Mathematics
2 answers:
Alex3 years ago
6 0
Depends on how much sunlight it gets
marissa [1.9K]3 years ago
4 0

Answer:

It depends on how much sun the place receives, how much it is shaded. temperature in the area. Do you have solar panels, electric heat, gas? All these factors determine utility cost.

Step-by-step explanation:

You might be interested in
A circular pizza that is 18 inches in diameter is cut into 8 equal slices. What is the area of a single slice?
Fiesta28 [93]

Answer:

31.8 in^2

Step-by-step explanation:

The area of a circle is pi×radius^2.

r=.5d=18/2=9

A=(3.14159)(9^2)=(3.14159)(81)=254.5

And if each peice is of equal area, the area of one peice will equal:

254.5/8=31.8

6 0
3 years ago
Order the numbers from least to greatest -4 -4.35 -4.9 -5 and -4.3
Natalija [7]

Answer:

-5,-4.9,-4.35,-4.3,-4

Step-by-step explanation:

Hope this helps :)

3 0
2 years ago
Solve for x in the equation 2x^2+3x-7=x^2+5x+39
Shalnov [3]
Hey there, hope I can help!

\mathrm{Subtract\:}x^2+5x+39\mathrm{\:from\:both\:sides}
2x^2+3x-7-\left(x^2+5x+39\right)=x^2+5x+39-\left(x^2+5x+39\right)

Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
x^2-2x-46=0

Lets use the quadratic formula now
\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}
x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:} a=1,\:b=-2,\:c=-46: x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\left(-46\right)}}{2\cdot \:1}

\frac{-\left(-2\right)+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \  \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \frac{2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}

Multiply the numbers 2 * 1 = 2
\frac{2+\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}

2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \  \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}

\mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \sqrt{\left(-2\right)^2+1\cdot \:4\cdot \:46} \ \textgreater \  \left(-2\right)^2=2^2, 2^2 = 4

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:1\cdot \:46=184 \ \textgreater \  \sqrt{4+184} \ \textgreater \  \sqrt{188} \ \textgreater \  2 + \sqrt{188}
\frac{2+\sqrt{188}}{2} \ \textgreater \  Prime\;factorize\;188 \ \textgreater \  2^2\cdot \:47 \ \textgreater \  \sqrt{2^2\cdot \:47}

\mathrm{Apply\:radical\:rule}: \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b} \ \textgreater \  \sqrt{47}\sqrt{2^2}

\mathrm{Apply\:radical\:rule}: \sqrt[n]{a^n}=a \ \textgreater \  \sqrt{2^2}=2 \ \textgreater \  2\sqrt{47} \ \textgreater \  \frac{2+2\sqrt{47}}{2}

Factor\;2+2\sqrt{47} \ \textgreater \  Rewrite\;as\;1\cdot \:2+2\sqrt{47}
\mathrm{Factor\:out\:common\:term\:}2 \ \textgreater \  2\left(1+\sqrt{47}\right) \ \textgreater \  \frac{2\left(1+\sqrt{47}\right)}{2}

\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \  1+\sqrt{47}

Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.

\frac{-\left(-2\right)-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \  \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \frac{2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}

\frac{2-\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}

2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \  2-\sqrt{188} \ \textgreater \  \frac{2-\sqrt{188}}{2}

\sqrt{188} = 2\sqrt{47} \ \textgreater \  \frac{2-2\sqrt{47}}{2}

2-2\sqrt{47} \ \textgreater \  2\left(1-\sqrt{47}\right) \ \textgreater \  \frac{2\left(1-\sqrt{47}\right)}{2} \ \textgreater \  1-\sqrt{47}

Therefore our final solutions are
x=1+\sqrt{47},\:x=1-\sqrt{47}

Hope this helps!
8 0
3 years ago
Read 2 more answers
The amount of caffeine consumed from a glass of Diet Pepsi is proportional to the number of ounces that was drank. The table bel
Vilka [71]

Answer:

Constant of proportionality: k=3

Equation: c=3d

Step-by-step explanation:

By definition, Direct proportion equations have the following form:

y=kx

Where "k" is the Constant of proportionality.

In this case, let be "c"  the the amount of caffeine consumed  (in mg) from a glass of Diet Pepsi and "d" the number of ounces that was drank.

So, the equation that represents this relationship will have this form:

c=kd

Then, the first step is to find the Constant of proportionality "k".

Knowing that:

c=24;d=8

We can substitute values into the equation:

24=k(8)

Now, solving for "k", we get:

\frac{24}{8}=k\\\\k=3

Therefore, we can write the following equation that represents that proportional relationship:

c=3d

6 0
3 years ago
Find the Geometric Mean of 4 and 9. (round to the nearest tenth)
Ainat [17]

Answer:

6

Step-by-step explanation:

Formula - √a * b

= √4 * 9

= √36

= 6

8 0
3 years ago
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