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I am Lyosha [343]
3 years ago
6

If the distance between the 2 and the 3 and the 6 and the 7 on a scale are equal, the scale would likely be at least:

Mathematics
1 answer:
irina [24]3 years ago
3 0
The scale is likely linear, with equal divisions between consecutive integers.  Two and three differ by one, as do 6 and 7.  Both "ones" are represented on the scale by equal distances.

There are many scales, such as logarithmic, on which equal differences are represented by UNEQUAL distances.
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What is the domain and range of y=x^2?
r-ruslan [8.4K]
Hi there! the best way of solving this is picturing out what the graph might look like. Let's assume you had the graph of a parabola y=x^2. You know that for every x you substitute, there'd always be a value for y. Thus, the domain is ALL REAL NUMBERS or from -INFINITY to + INFINITY. The range on the other hand is different. We know that any number raised to the second power will always yield a positive integer or 0. Thus, y=x^2 won't have any negative y-values as the graph opens upward. Therefore, the range is: ALL REAL NUMBERS GREATER THAN OR EQUAL TO 0. or simply: 0 to +INFINITY. 

<span>On the other hand, a cubic function y=x^3 is quite different from the parabola. For any x that we plug in to the function, we'd always get a value for y, thus there are no restrictions. And the domain is ALL REAL NUMBERS or from -INFINITY to + INFINITY. For the y-values, the case would be quite similar but different to that of the y=x^2. Since a negative number raised to the third power gives us negative values, then the graph would cover positive and negative values for y. Thus, the range is ALL REAL NUMBERS or from -INFINITY to + INFINITY. Good luck!!!:D</span>
3 0
3 years ago
Read 2 more answers
The midpoint of the line segment with end points (-3,1) and (1,-4) is (-1,-1.5) <br><br> Yes or no?
blsea [12.9K]

Answer:

Answer: yes.

Step-by-step explanation:

x: (x1 + x2)/2 = (-3 + 1)/2 = -2/2 = - 1 So far so good.

y: (y1 + y2)/2 = (1 - 4 )/2 = (-3/2) = -1.5

The midpoint is (-1 , - 1.5)

True

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3 years ago
What is the seventh term in the arithmetic sequence?<br> 3, 11, 19, 27,
Sergio [31]
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What is the product? startfraction 2 y over y minus 3 endfraction divided by startfraction 4 y minus 12 over 2 y 6 endfraction t
Genrish500 [490]

The product of the expression \rm \dfrac{\dfrac{2y}{y-3} }{\dfrac{4y-12}{2y+6}}\\\\\\ is \rm \dfrac{(y^2+3y)}{(y^2-6y+9)}\\.

<h3>What is the product?</h3>

In mathematics, the term 'product' refers to the answer to a multiplication problem.

The product of the given expression is determined in the following steps given below.

\rm =\dfrac{\dfrac{2y}{y-3} }{\dfrac{4y-12}{2y+6}}\\\\\\=\dfrac{2y}{y-3}\times \dfrac{2y+6}{4y-12}\\\\= \dfrac{2y \times 2y + 2y \times 6}{y(4y-12)-3(4y-12)}\\\\=\dfrac{4y^2+12y}{4y^2-12y-12y+36}\\\\=\dfrac{4y^2+12y}{4y^2-24y+36}\\\\=\dfrac{4(y^2+3y)}{4(y^2-6y+9)}\\\\ =\dfrac{(y^2+3y)}{(y^2-6y+9)}\\

Hence, the product of the expression \rm \dfrac{\dfrac{2y}{y-3} }{\dfrac{4y-12}{2y+6}}\\\\\\ is \rm \dfrac{(y^2+3y)}{(y^2-6y+9)}\\.

To know more about the product click the link given below.

brainly.com/question/15029466

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Let x represent an even integer. Which expression represents the next even integer?
polet [3.4K]
A 2x is the right answer
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