We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.
The value of x is
<span>
5 feet. </span>
Answer: 6
<u>Step-by-step explanation:</u>
NOTE: log₆6 = 1
log₆6 + log₆(x - 5) = log₆6
1 + log₆(x - 5) = 1
log₆(x - 5) = 0
x - 5 = 6⁰
x - 5 = 1
x = 6
This is a division we can write those numbers as fractions to make it simpler
0.16=
0.064=
when we divide two fractions we can multiply the divided with the inverse divisor

we simplify

which is equal to

or

we can leave it like this or divde to get
2.5
V = LWH
6400 = (4W) * W * 4
1600 = 4W^2
400 = W^2
W = 20
L = 4(20)
L = 80
W = 20 ft
L = 80 ft