Ralph sold brownies for $0.18 a piece in order to earn money to buy baseball cards. If the cards cost $0.36 per pack, and if
Ralph had no money left over after buying them, what is the least number of brownies he must have sold?
1 answer:
The least number of brownies that he must have sold was 2.
$0.18 x 2 = $0.36
$0.36 - $0.36 = $0.00
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= 2^-16 * 3^10 *3^-8/ 2^12 * 2^28
= 2^(-16 - 12 + 28) * 3^(10 - 8)
= 2^0 * 3^2
= 9
answer
9
Answer:10151 will be your answer
Step-by-step explanation:
Answer:
.12g of Na
Step-by-step explanation:
We simply substitute 6 into the equation:
f(6) = -2(6 - 4)² + 22
f(6) = 14
The company's profit is 14 thousand dollars
hope it helped :).
Answer:
solution is -6/5 because:
-1/2(5x-8)=7
-5x+8/2=7
-5x+8=7*2
-5x+8=14
-5x=14-8
-5x=6
x=-6/5
