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3 years ago

What is the value of g?

Mathematics

1 answer:

MAVERICK [17]3 years ago

4 0

Answer:

Step-by-step explanation:

iwan dko rin Alam sagot sorry

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Carolyn swim 35 laps in 1/2 hour. How far will she swim in 4 hours? Please help.

NARA [144]

70 laps in 40 hours

1/2+1/2=4

35+35=70
I think

3 0

3 years ago

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Solving systems of equations using substitution y=2x Y=-2x-4 X= Y=

podryga [215]

Answer:

hope this helps

Step-by-step explanation:

y=2x

y=-2x-4

2x+2x=-4 (grouping like terms)

4x=-4

x=-1

im sorry but im not sure what y is

6 0

3 years ago

Simplified form of 4x - (2 – 3x) + 5?

prisoha [69]

7x + 3 is the final answer

8 0

3 years ago

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Find the minimum value of the function f(x)=x^2+5x-6

mash [69]

<h3><u>Explanation</u></h3>

Method 1 (Formula)

$\begin{cases}h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{2a} \end{cases}$

The vertex of Parabola is the maximum/minimum point depending on the value of a.

Find Vertex

<u>h-value</u>

$h = - \frac{5}{2(1)} \\ h = - \frac{5}{2}$

<u>k-value</u>

$k = \frac{4(1)( - 6) - {(5)}^{2} }{4(1)} \\ k = \frac{ - 24 - 25}{4} \\ k = \frac{ - 49}{4} \\ k = - \frac{49}{4}$

The minimum value is the value of k. Therefore the minimum value is - 49/4 at x = -5/2.

Method 2 (Derivative)

This is Calculus method. We simply differentiate the function then substitute y' = 0.

Differentiate Function

$f'(x) = 2 {x}^{2 - 1} + {5x}^{1 - 1} - 0 \\ f'(x) = 2x + 5$

Substitute f'(x) = 0

$0 = 2x + 5 \\ - 5 = 2x \\ - \frac{5}{2} = x$

Substitute x = -5/2 in the original equation.

$f(x) = {( - \frac{5}{2} )}^{2} + 5( - \frac{5}{2} ) - 6 \\ f(x) = \frac{25}{4} - \frac{25}{2} - 6 \\ f(x) = \frac{25}{4} - \frac{50}{4} - \frac{24}{4} \\ f(x) = \frac{25}{4} - \frac{74}{4} \\ f(x) = - \frac{49}{4}$

<h3><u>Answer</u><u /></h3>

<u> $\sf{the \: \: minimum \: \: value \: \: is \: \: - \frac{49}{4} \: \: at \: \: x = - \frac{5}{2} }$ </u>

4 0

3 years ago

Use the “complete the square” method to rewrite the equation ax 2 + bx + c = 0 in the form ( x – p ) 2 = q .

mel-nik [20]

Ax2<span> + bx + c = 0 = </span>a(x+d)^2<span> + </span>e<span> = 0 </span>

3 0

3 years ago

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