All categories

3 years ago

8CO + 17H2 → C8H18 + 8H2O

Chemistry

1 answer:

liq [111]3 years ago

5 0

Answer: 27,625 grams

Explanation:

*This is actually pretty simple

According to your equation, we know that:

8 moles of CO will react completely with 17 moles of H2

so:

6.50 moles of Co will react completely with x moles of H2

x= (6.50 x 17)/8 = 13.8125 (moles)

Since the Molar Mass of H2 is 2 g/mol, we can calculate the amount of H2 needed to react completely with 6.50 moles of CO:

=>13.8125 x 2= 27.625 (grams)

You might be interested in

What is the molecular formula of a compound with an empirical formula of C4H9 and a gram-formula mass of 114.0 g/mole?

hodyreva [135]

The formula is easy:

Gram formula mass
----------------------------
Emprical Formula

So if we plug in our own numbers,

114.0
--------
57.116

We get an answer of 1.99, which rounds to 2.
Then, we distribute based off of our empirical formula.

2(C4H9) becomes C8H18.

Our molecular formula is C8H18.
Hope I could help!

6 0

4 years ago

In water, Vanillin, C8H8O3, has a solubility of 0.070 moles of vanillin per liter of solution at 25C. What will be produced if 5

Rufina [12.5K]

Answer:

The full amount (5.00 g) will be dissolved in 1 L of water at 25°C.

Explanation:

The molecular weight (MW) of Vanillin (C₈H₈O₃) is calculated from the chemical formula as follows:

MW(C₈H₈O₃) = (12 g/mol x 8) + (1 g/mol x 8) + (16 g/mol x 3) = 152 g/mol

If 0.070 mol of C₈H₈O₃ are soluble per liter of water at 25°C, the maximum mass that can be dissolved in 1 L is:

0.070 mol x 152 g/mol = 10.64 g

Since 5.00 g is lesser than the maximum amount that can be dissolved (10.64 g), the added amount will be completely dissolved in 1 L of water at 25°C.

7 0

3 years ago

What phase of matter is least common on earth

Diano4ka-milaya [45]

Plasma is the least common matter on earth

4 0

3 years ago

Which property is shared by both acids and bases?

Evgen [1.6K]

$\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}$

3. Conducts electricity in aqueous solution.

Thanks
Hope it helps.

3 0

3 years ago

For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

3 years ago