All categories

1 year ago

Distinguish between a correlation and an autocorrelation. how are these measures similar? how are they different?

1 answer:

3 0

A correlation is a causative association between two or more variables, whereas an autocorrelation is a correlation of variables in successive ranges.

<h3>What is correlation?</h3>

A correlation is defined as a causative association between two or more variables (different variables), which can be used to make predictions about a given outcome.

The correlation coefficient enables the estimation of this association between different variables.

Moreover, an autocorrelation is a special type of correlation between variables that can be found in successive ranges (e.g. range time intervals).

In conclusion, a correlation is a causative association between two or more variables, whereas an autocorrelation is a correlation of variables in successive ranges.

Learn more about correlation here:

brainly.com/question/11811889

#SPJ1

You might be interested in

Help me with my algebra homework 1/4

Margaret [11]

Answer:

1) 24 2) $2 per pencil 3) 23 4) 15 5) $5 per eraser

6) 37 7) 16 8) $16

Step-by-step explanation:

hope this helps

5 0

3 years ago

6.1.3

Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are µ = 0 and σ = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.

If X $\sim$ N (µ, σ²), then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z $\sim$ N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are µ = 0 and σ = 1.

8 0

3 years ago

The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =

gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy is given as :

$f_x(x) = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0$

Thus, the expected total claim amount $\mu$ = 1000

The variance of the total claim amount $\sigma ^2 = 1000^2$

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

$P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})$

$P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})$

$P(X>1100n) = P(Z> \dfrac{10*100}{1000})$

$P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345$

$\mathbf{P(X>1100n) = 0.158655}$

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

4 0

2 years ago

If you don't have two rays, can you have an angle?

Triss [41]

Answer:

Yes

Step-by-step explanation:

You can define an angle of interest at any point of intersection of any real or virtual lines, curves, planes, or surfaces, or combination thereof. We often measure the angle between our present location and two different other locations (horizon, stars, objects of one sort or another). The "rays" involved are virtual (non-existent, imaginary, conceptual) rather than real. We also often measure angles between real physical objects, things other than the idealized set of infinitesimal points that make up a ray.

6 0

3 years ago

The base of a rectangular prism has an area of 25 square meters. The height of the rectangular prism is 4 meters. What is the vo

lys-0071 [83]

Given:

The base of a rectangular prism has an area of 25 square meters. The height of the rectangular prism is 4 meters.

We need to determine the volume of the rectangular prism.

Volume of the rectangular prism:

The volume of the rectangular prism can be determined using the formula,

$V=Bh$