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1 year ago

Distinguish between a correlation and an autocorrelation. how are these measures similar? how are they different?

1 answer:

3 0

A correlation is a causative association between two or more variables, whereas an autocorrelation is a correlation of variables in successive ranges.

<h3>What is correlation?</h3>

A correlation is defined as a causative association between two or more variables (different variables), which can be used to make predictions about a given outcome.

The correlation coefficient enables the estimation of this association between different variables.

Moreover, an autocorrelation is a special type of correlation between variables that can be found in successive ranges (e.g. range time intervals).

In conclusion, a correlation is a causative association between two or more variables, whereas an autocorrelation is a correlation of variables in successive ranges.

Learn more about correlation here:

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The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago

HURRRYYYYYYY HE KEEPS ASKING FOR THE ANSWER IF I DONT TURN IT IN IM GETTING A REFERAL

monitta

Answer:

I think it is 150 miles between Phoenix and Atlanta

Step-by-step explanation:

(2.9,-4.2)-(2.4,-4.2)=(0.5,0)

0.5 is half of 1 and 150 is half of 0.5

8 0

2 years ago

Please help me with this!!

SashulF [63]

Answer:

Step-by-step explanation:

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3 years ago

What is 4x - 2 = 22 8x x =

EleoNora [17]

I think the answer is x = -4.

7 0

3 years ago

Write an equation of a line containing (2, -3) and perpendicular to 3x+4y=14 answer

Sergio039 [100]

Answer:

Step-by-step explanation:

From the condition of perpendicularity, if two lines must be perpendicular to each other, the product of their gradient rather the slope must be equaled to ( -1 ).

Equation of a line ; y = mx+ c, where m1 is the gradient of the line and c us the point of intersection if the line on the y- axis.therefore, the equation

3x + 4y = 14, when re arranged, now becomes, 4y = -3x + 14, divide through by 4, gives, y = -3x/4 + 14.

Therefore, m1, = -3/4 and m2, = 4/3 going by the condition. Since the line passes through the coordinate of (2,3), where x = 2, and y = -3, then, substitute for x and y in y = mx+ c, minding the m2, to find C, therefore,

-3 = 4/3x2 + c. -3 = 8/3 +c

Multiply through by 3 to make it a linear equation,

-9 = 8 + 3c; -9 - 8 = 3c, -17= 3c

c = -17/3.Now substitute for c in the equation ,y = mx+ c, the equation now becomes, y = 4x/3 - 17/3. Therefore the new equation is

3y = -4x - 17.

7 0

3 years ago