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2 years ago

7

Can some one please help me on my home work please i just need some one to show me how they solved this equation answers and wor

k please. 5(y+2)=4(x-3) please show work again.

1 answer:

nignag [31]2 years ago

3 0

Step-by-step explanation:

well first of all you have to expand the brackets. so 5(y+2)=4(x-3)

5y+10=4x-12

then you subtract 10

5y=4x-12-10=4x-22

then divide by 5 to get the value of y

y=(4x-22)/5

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a)

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$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

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