F = 1.8C + 32
С = -10 ⇒ F = 1.8·(-10) + 32 = 14 ⇒
(-10, 14)С = 0 ⇒ F = 1.8·(0) + 32 = 32 ⇒
(0, 32)
С = 10 ⇒ F = 1.8·(10) + 32 = 50 ⇒
(10, 50)С = 20 ⇒ F = 1.8·(20) + 32 = 68 ⇒
(20, 68)
let the two numbers be x and y
From the first sentence,
xy=24
x+y=10
Then make y in equation 2 the subject of the formular and substitute in equation 1
x+y=10
y=10-x
substituting in equation 2
x(10-x)=24
open the bracket
10x-x^2=24
=-x^2+10x=24
Transfer the constant to the left hand side
=-x^2+10x-24=0
Then factorise completely
Look at the photo above
I think the second one does
Answer:
17/12
Step-by-step explanation:
i hope this is right