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4vir4ik [10]
2 years ago
6

bennett was visiting five cities that lie on a coordinate grid at A(-2,3), B(2,7), C(7,8), D(6,3) and E(2,-1). What is the midpo

int between A and E
Mathematics
1 answer:
bezimeni [28]2 years ago
5 0

The midpoint between A and E is (0,1)

<h3>How to determine the midpoint between A and E?</h3>

The coordinates of the cities are given as:

A(-2,3), B(2,7), C(7,8), D(6,3) and E(2,-1).

From the above, we have:

A = (-2,3)

E = (2,-1)

The midpoint between A and E is calculated using

Midpoint = 1/2 * (x1 + x2, y1 + y2)

Substitute the known values in the above equation

Midpoint = 1/2 * (-2 + 2, 3 - 1)

This gives

Midpoint = 1/2 * (0, 2)

Evaluate the product

Midpoint = (0, 1)

Hence, the midpoint between A and E is (0,1)

Read more about midpoint at

brainly.com/question/5566419

#SPJ1

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If PQ = 6x - q and PR = 15x - 29, then QR =?
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Determine 7th term in the geometric sequence whose first term is 5 and whose common ratio is 2.
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Find the product. (2n + 2)(2n – 2)
vekshin1
<span>(2n + 2)(2n – 2)
= (2n)^2 -2^2
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hope it helps</span>
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Find the difference. (7x-6 2/3) - (-3x + 4 3/4)
NikAS [45]

10x-61/12 is the difference of  (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4}).

<h3>What is Expression?</h3>

An expression is combination of variables, numbers and operators.

The given expression is (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4})

7x-6\frac{2}{3}+3x- 4\frac{3}{4}

7x-20/3+3x-19/4

Add the variable terms and constant terms.

10x-20/3-19/4

The LCM of 3 and 4 is 12/

10x-4-57/12

10x-61/12

Hence, 10x-61/12 is the difference of  (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4}).

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4 0
1 year ago
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