Question

What is the solution to the following equation? x2 + 3x + 4 = 0​

Answer 1

Answer:

$x=\dfrac{-3\pm \sqrt7i}{2}$

Step-by-step explanation:

The given equation is $x^{2}+3x+4=0$.

We need to find the solution of the above equation.

The solution of an equation $ax^2+bx+c=0$ is :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

We have, a = 1, b = 3 and c = 4

$x=\dfrac{-3+ \sqrt{(3)^2-4(1)(4)} }{2}, \dfrac{-3- \sqrt{(3)^2-4(1)(4)} }{2}\\\\=\dfrac{-3+\sqrt{9-16}}{2}, \dfrac{-3-\sqrt{9-16}}{2}\\\\=\dfrac{-3\pm \sqrt7i}{2}$

So, the solution of the given equation is $\dfrac{-3\pm \sqrt7i}{2}$.