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Scrat [10]
3 years ago
5

If a kid was playing for 4 hours and he did 9 activitys how much time did each activity take

Mathematics
2 answers:
bezimeni [28]3 years ago
6 0

Answer:

<em>26.6666666667</em>

Step-by-step explanation:

First, you will need to convert 4 hours into minutes. 60×4=240

After you have converted the hours into minutes, you will need to use that number divide it by the number of activities. Witch in your case, would be 9.

<em>240÷9=26.6666666667</em> If the answer is not there <em>round it to: 26.67</em>

<em><u>Mark brainliest?</u></em>

nadezda [96]3 years ago
3 0

Answer:

26.6667 minutes or 0.444 hours per activity.

Step-by-step explanation:

If he spent an equal amount of time on each activity, then it would have to be divided equally: 4hours/9

In minutes:

4 x 60 = 240 minutes

240/9

26.6667 minutes per activity.

In Hours:

4/9

0.444 hours per activity.

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3 years ago
Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,
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Answer:

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Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is   \dfrac{1}{6} .

      Numbers on the dice (X)                       P(X)

                      +1                                                 \frac{1}{6}

                      +2                                                \frac{1}{6}

                      +3                                                \frac{1}{6}

                      -4                                                 \frac{1}{6}

                      +5                                                \frac{1}{6}

                      -6                                                 \frac{1}{6}

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X)  =  \sum X \times P(X)

   =  (+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}

   =  \frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}

   =  \frac{1+2+3-4+5-6}{6}

   =  \frac{11-10}{6}= \frac{1}{6}

Hence, the expected value of the points earned on a single roll in this game is  \frac{1}{6} = 0.1667 .

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