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2 years ago

. Factorise the following expression fully(a+1)²-4b²

Mathematics

1 answer:

Marat540 [252]2 years ago

7 0

The factoring the equation (a + 1)² - 4b² we get (a+1+2b)(a+1-2b).

<h3>What is the factoring function of (a + 1)² - 4 b²?</h3>

Given: (a + 1)² - 4b²

Apply Perfect Square Formula, and we get

(a + b)² = a² + 2 a b + b²

(a + 1)² = a² + 2a1+1²

= a² + 2a1 + 1² - 4 b²

simplifying the equation, we get

a² + 2a1 + 1² = a² + 2a + 1

= a² + 2a + 1 - 4b²

Factor, a² + 2a + 1 = (a + 1)²

= (a + 1)² - 4 b²

Simplify 4 b² = (2 b)²

= (a + 1)² - (2b)²

Apply the Difference of Two Squares Formula, and we get

x² - y² = (x + y)(x - y)

(a + 1)² - (2b)² = ((a + 1) + 2b)((a + 1) - 2 b)

simplifying the equation, we get

= ((a + 1) + 2b)(a + 1) - 2 b)

= (a + 1 + 2b)(a + 1 - 2b)

Therefore, the correct answer is (a+1+2b)(a+1-2b).

To learn more about factoring refer to:

brainly.com/question/25829061

#SPJ9

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It says vertex so I'm thinking you meant $y=-2(x+2)^2+2$ . Please correct me if I'm wrong.

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. Factorise the following expression fully(a+1)²-4b²​

. Factorise the following expression fully(a+1)²-4b²