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velikii [3]
3 years ago
9

Which binomial is a factor of 9x2 + 24xy + 16y2?

Mathematics
1 answer:
ohaa [14]3 years ago
8 0

Option A

The binomial factor is 3x + 4y

<em><u>Solution:</u></em>

We have to find the binomial factor of given equation

<em><u>Given equation is:</u></em>

9x^2+24xy+16y^2

<em><u>Let us factor the given expression</u></em>

9x^2+24xy+16y^2

\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2\\\\=3^2x^2+24xy+16y^2\\\\\mathrm{Rewrite\:}16\mathrm{\:as\:}4^2\\\\=3^2x^2+24xy+4^2y^2\\\\\mathrm{Apply\:exponent\:rule}:\quad \:a^mb^m=\left(ab\right)^m\\\\3^2x^2=\left(3x\right)^2\\\\=\left(3x\right)^2+24xy+4^2y^2\\\\\mathrm{Apply\:exponent\:rule}:\quad \:a^mb^m=\left(ab\right)^m\\\\4^2y^2=\left(4y\right)^2

=\left(3x\right)^2+24xy+\left(4y\right)^2\\\\\mathrm{Rewrite\:}24xy\mathrm{\:as\:}2\cdot \:3x\cdot \:4y\\\\=\left(3x\right)^2+2\cdot \:3x\cdot \:4y+\left(4y\right)^2\\\\ \mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2\\\\a=3x,\:b=4y\\\\=\left(3x+4y\right)^2\\\\\rightarrow (3x+4y)^2 = (3x+4y)(3x+4y)

Thus the binomial factor is 3x + 4y

Thus Option A is correct

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Answer:

y = -1/2x + 1

Step-by-step explanation:

Using the slope formula: y = (y2 - y1)/(x2 - x1), we can determine that the slope is -1/2. There is only one answer with the slope of -1/2, but to check that it's right, we can plug in one of the points to see that y = -1/2x + 1 works.

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Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
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Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

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Answer:

The proof is derived from the summarily following equations;

∠FBE + ∠EBD = ∠CBA + ∠CBD

∠FBE + ∠EBD = ∠FBD

∠CBA + ∠CBD = ∠ABD

Therefore;

∠ABD ≅ ∠FBD

Step-by-step explanation:

The two column proof is given as follows;

Statement {}                                       Reason          

\underset{BD}{\rightarrow} bisects ∠CBE {}                            Given

Therefore;

∠EBD ≅ ∠CBD  {}                              Definition of angle bisector

∠FBE ≅ ∠CBA {}                                Vertically opposite angles are congruent

Therefore, we have;

∠FBE + ∠EBD = ∠CBA + ∠CBD {}     Transitive property

∠FBE + ∠EBD = ∠FBD {}                    Angle addition postulate

∠CBA + ∠CBD = ∠ABD {}                   Angle addition postulate

Therefore;

∠ABD ≅ ∠FBD        {}                          Transitive property.

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Answer:

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