Answer:
I have placed it correct answers in the image above
Does not exist, since the graph of cosine is continuous between the intervals [-1,1]. You do not know where it will be when it “reaches” infinity
Answer:
$ 5674.076
Step-by-step explanation:
The question is on compound interest
The formulae = A= P(1+ r/n) ^nt .......where P is the principal amount, r is the rate of interest in decimal, n is number of compoundings per year and t is the total number of years.
Given; P= $4,000.00 , r=12/100=0.12, n=2 and t=3
Substituting values in the equation A= P(1+ r/n) ^nt
A= 4000 ( 1+0.12/2)^2×3
A=4000(1.06)^6
A=$ 5674.08
Answer:
So the right answer is none
Step-by-step explanation:
-6≤1+3x
3x≥-7
x≥-2,33
-2,33>-5>-6>-11
so none of those are bigger then -2,33 and x is bigger then -2,33
Answer:
f(n) = -n^2 -3n +5
Step-by-step explanation:
Suppose the formula is ...
f(n) = an^2 +bn +c
Then we have ...
f(1) = 1 = a(1^2) +b(1) +c
f(2) = -5 = a(2^2) +b(2) +c
f(3) = -13 = a(3^2) +b(3) +c
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Here's a way to solve these equations.
Subtract the first equation from the second:
-6 = 3a +b . . . . . 4th equation
Subtract the second equation from the third:
-8 = 5a +b . . . . . 5th equation
Subtract the fourth equation from the fifth:
-2 = 2a
a = -1
Then substituting into the 4th equation to find b, we have ...
-6 = 3(-1) +b
-3 = b
and ...
1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation
5 = c
The formula is ...
f(n) = -n^2 -3n +5
