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Alex17521 [72]
2 years ago
7

Which statement is not a step used when constructing an inscribed square?

Mathematics
1 answer:
Lilit [14]2 years ago
3 0

The statement that is not a step used when constructing an inscribed square is swing an arc the length of the radius from the point on the circle. Option B

<h3>Steps in inscribing a square</h3>

The steps involved in inscribing a square in a square are;

  • Use a compass to draw a circle and label the center
  • Draw a diameter of the circle using a straightedge
  • Then, construct the perpendicular bisector of the diameter
  • Label the points where the bisector intersects the circle
  • Connect the points  to form the square.

From the above steps, it can be concluded that swinging an arc the length of the radius from the point on the circle is not a step in inscribing a square.

Hence, the statement that is not a step used when constructing an inscribed square is swing an arc the length of the radius from the point on the circle. Option B

Learn more about an inscribed square here:

brainly.com/question/2458205

#SPJ1

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Please help immediately ​
Burka [1]

Answer:    f'(1)=\dfrac{4}{2y+1}

<u>Step-by-step explanation:</u>

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given:         0 = 2x² - xy - y²

Derivative:  0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

                   y'(2y + 1) = 4x

                   y'=\dfrac{4x}{2y+1}

\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}

8 0
3 years ago
Need the answer for my hw
andrew-mc [135]
The answer is (1,1)
5 0
2 years ago
In 16years, Ben will be 3 times as old as he is right now.
dedylja [7]

Answer:

Don't quote me on this but I believe the answer is that he is 8 years old right now if that's what you're looking for

Step-by-step explanation:

8 + 16 = 24

8 × 3 = 24

That's what I thought

5 0
3 years ago
What’s the trinomial Mila (x-6)^2
MatroZZZ [7]

Hello

(x-6)² = x² -6*2*x + 6²

= x² -12x + 36

8 0
3 years ago
Reposting this because no body gave me the equation. An equation would be appreciated :)
o-na [289]

bring the like terms together,

\frac{6q}{5}  +  \frac{4q}{5}  \leqslant 28 + 3 + 3 - 3

\frac{10q}{5}  \leqslant 31

2q \leqslant 31

q \leqslant  \frac{31}{2}

3 0
3 years ago
Read 2 more answers
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