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Fudgin [204]
3 years ago
7

Ajar contains 12 caramels, 7 mints and 16

Mathematics
1 answer:
tangare [24]3 years ago
7 0

Answer: 1/5

Step-by-step explanation: To find the probability of selecting a mint out of the jar, we use our ratio for the probability of an event which is shown below.

(P) event = <em>number of favorable outcomes/total number of outcomes</em>.

Since there are 7 mints in the jar, the number of favorable outcomes is 4 and since there are 35 candies in all,

the total number of outcomes is 35.

Therefore, the probability of selecting a mint is 7/35.

Notice however that 7/35 is not in lowest terms so we need to divide the numerator and denominator of 7/35 by their greatest common factor of 7 to get 1/5.

So our final answer for the probability of selecting a mint is 1/5.

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The question said that it told you the base angles. A roof would have two equal base angles. The base angles= 53

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So, let's make x the missing angle.

53(2)+x=180

106+x=180

Subtract 106 on both sides.

180-106= 74

The vertex angle is 74.

I hope this helps!
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Given f(x) = x^2-3 and g(x)=x+2/x. Find (g°f)(4)
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Which expression is equivalent to
lutik1710 [3]

Answer:

\frac{\sqrt[4]{3x^2} }{2y}

Step-by-step explanation:

We can simplify the expression under the root first.

Remember to use  \frac{a^x}{a^y}=a^{x-y}

Thus, we have:

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We know 4th root can be written as "to the power 1/4th". Then we can use the property  (ab)^{x}=a^x b^x

<em>So we have:</em>

<em>\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}</em>

<em />

<em>Option D is right.</em>

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