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2 years ago

Solve for m: 18d-2m+9k<5k+10

1 answer:

5 0

Subtract 18d + 9k from both sides
-2m < -4k - 18d + 10
Multiply both sides by -1
2m > 4k + 18d - 10
Then divide both sides by 2 to get the final answer:
m > 9d + 2k - 5

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Can anybody help me with this

ivolga24 [154]

A = (4, 5) B = (-2, 1)

Midpoint of A and B

$C=(X_M, Y_M) = \bigg(\dfrac{X_A+X_B}{2}, \dfrac{Y_A+Y_B}{2}\bigg)\\\\. \qquad \qquad \qquad =\bigg(\dfrac{4-2}{2},\dfrac{5+1}{2}\bigg)\\\\. \qquad \qquad \qquad =\bigg(\dfrac{2}{2},\dfrac{6}{2}\bigg)\\\\. \qquad \qquad \qquad =(1, 3)$

Distance from A to B

$d_{AB}=\sqrt{(X_B-X_A)^2+(Y_B-Y_A)^2}\\\\.\qquad =\sqrt{(-2-4)^2+(1-5)^2}\\\\.\qquad =\sqrt{(-6)^2+(-4)^2}\\\\.\qquad =\sqrt{36+16}\\\\.\qquad =\sqrt{52}\\\\.\qquad =7.2$

Equation of line through AB

$m_{AB}=\dfrac{Y_B-Y_A}{X_B-X_A}\\\\.\qquad =\dfrac{1-5}{-2-4}\\\\.\qquad =\dfrac{-4}{-6}\\\\.\qquad =\dfrac{2}{3}$

$Y-Y_A=m_{AB}(X-X_A)\\\\Y-5=\dfrac{2}{3}(X-4)\\\\Y-5=\dfrac{2}{3}X-\dfrac{8}{3}\\\\Y=\dfrac{2}{3}X+\dfrac{7}{3}$

Line parallel to AB (same slope as AB) through point (3, -5)

$Y-Y_A=m_{AB}(X-X_A)\\\\Y+5=\dfrac{2}{3}(X-3)\\\\Y+5=\dfrac{2}{3}X-2\\\\Y=\dfrac{2}{3}X-7$

AB is perpendicular to A'B' so slopes are opposite reciprocals

A' = (3, 0)

B' = (-1, 6)

C = (1, 3)

C' = (7, 3)

D = (5, 3)

D' = (5, 1)

3 0

2 years ago

What is the slope of the line shown above?

netineya [11]

Answer:

The slope of the line is 2/3x

Step-by-step explanation:

To find the slope, you need to choose two points and find the change of y over the change of x (also know as rise/run).

Let's focus on points (-3, -1) and (0, 1).

To get from the first point to the other, you would need to move 2 units up, and 3 units to the right.

3 0

2 years ago

Read 2 more answers

Please help as soon as possible

Crank

Answer:

$9 \times 3 = 27 \\ 15 \times 6 = 90 \\ = 30.255 \\ 49 \times 3.14 = 153.86 \\ 153.86 + 30.255 + 27 = 211.115$

6 0

2 years ago

Grady marks down some $4.09 pens to $3.59 for a week and then marks them back up to $4.09. Find the percent of increase and the

emmainna [20.7K]

Answer:

Percentage decrease ( from $4.09 to $3.59) is 0.1% ( Rounded to nearest tenth)

Percentage increase (from $3.59 to 4.09) is 0.1% ( Rounded to nearest tenth)

Percentages are not same for the both price changes. As we can see from the calculations percentage change from $3.59 to $4.09 is higher.

Step-by-step explanation:

$4.09 has been changed to $3.59.

Percent change = [(Value after - Value before) / Value before]*100

= $\frac{3.59-4.09}{4.09}*100$ %

= $\frac{-0.5}{4.09}*100$ %

= $-0.122249$ %

= $-0.1$ % ( Rounded to nearest tenth)

Percentage decrease is 0.1% ( Rounded to nearest tenth)

Now lets calculate the percentage change from $3.59 to $4.09.

Percent change = [(Value after - Value before) / Value before]*100

= $\frac{4.09-3.59}{3.59}*100$ %

= $\frac{0.5}{3.59}*100$ %

= $0.13927$ %

= $0.1$ % ( Rounded to nearest tenth)

Percentage increase is 0.1% ( Rounded to nearest tenth)

Percentages are not same for the both price changes. As we can see from the calculations percentage change from $3.59 to $4.09 is higher.

6 0

3 years ago

Show answer in lowest terms.3/4 + 8/9

DiKsa [7]

3/4 + 8/9

= (3*9)+(4*8) / (4*9)

= 27+32 / 36

= 59/36

= 1 23/36

7 0

2 years ago

Read 2 more answers