two buildings are built 10m apart. *the angle of depression from the top of the shorter building (y) to the foot of the taller b
1 answer:
The height of the taller building is 18.6 meters
<h3>How to find the side of a right triangle?</h3>A right triangle has one of its angles as 90 degrees. The side of a right angle triangle can be found using trigonometric ratios.
Therefore, the height of the taller building is the sum of the height of the smaller building and upper part of the taller building.
tan 53 = opposite / adjacent
tan 53 = x / 10
cross multiply
x = 10 tan 53
x = 10 × 1.32704482162
x = 13.2704482162
x = 13.3 m
tan 28 = y / 10
y = 10 tan 28
y = 5.31709431661
y = 5.3
Therefore, the height of the taller building is 13.3 + 5.3 = 18.6 meters.
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First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:
The figure would look kinda like this:
R
M
S
B
Diagonals are segment RB and segment SM
So, your slope equations would look like this:
and
Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram
Formulas needed:
Slope formula:
The figure would look kinda like this:
R
M
S
B
Diagonals are segment RB and segment SM
So, your slope equations would look like this:
and
Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram