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Hatshy [7]
3 years ago
12

It has been reported that the average credit card debt for college seniors is $3262. The student senate at a large university fe

els that their seniors have a debt much less than this, so it conducts a study of 50 randomly selected seniors and finds that the average debt is $2995, and the population standard deviation is $1100. At α = 0.05, is the student senate correct? a) State the hypotheses and identify the claim with the correct hypothesis
Mathematics
1 answer:
xeze [42]3 years ago
4 0

Answer:

Following are the solution to the given point:

Step-by-step explanation:

The formulated null hypothesis would be that the reported average do not differ significantly

H_o : \mu = \$3262\\\\H_a :  \mu <  \$3262 \ \text{(One tailed test)}

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Doss [256]
Linear functions are given in the form:
y = mx + n
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Inserting the given values:
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olutions At the snack bar, hot dogs cost $4 each and bottled water costs $2 each. In the first business hour of the day, less th
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To solve the problem it is trial and error since we don’t know how many hotdogs and bottled water was sold. To trim down to problem, negative values and decimal values are not included because there is no negative amount and a decimal amount.

The equation is

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12 > 12 so it is wrong

At ( 2,1)

4(2) + 2(1) > 12

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7 0
4 years ago
Find the area of the shaded region 6cm 6cm
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4 0
3 years ago
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user100 [1]

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c

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
There are 6 students. 2 of them are chosen for the position of president and Vice President. How many ways do we have to choose
Nutka1998 [239]

We have 15 ways to chose 2 students for the position of president and Vice President

<em><u>Solution:</u></em>

Given that,

There are 6 students. 2 of them are chosen for the position of president and Vice President.

<em><u>To find: number of ways we have to choose the students from the 6 students</u></em>

So now we have 6 students, out of which we have to choose 2 students

As we just have to select the students. We can use combinations here.

In combinations, to pick "r" items from "n" items, there will be ^{\mathrm{n}} \mathrm{C}_{\mathrm{r}} ways

^{\mathrm{n}} \mathrm{C}_{\mathrm{r}}=\frac{n !}{(n-r) ! r !}

<em><u>Then, here we have to pick 2 out of 6:</u></em>

Total students = n = 6

students to be selected = r = 2

\begin{aligned} 6 C_{2} &=\frac{6 !}{(6-2) ! 2 !} \\\\ 6 C_{2} &=\frac{6 !}{4 ! 2 !} \\\\ 6 C_{2} &=\frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1 \times 2 \times 1} \\\\ 6 C_{2} &=15 \end{aligned}

Thus we have 15 ways to chose 2 students for the position of president and Vice President

3 0
3 years ago
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