All categories

2 years ago

PLEASE HELP "

Mathematics

1 answer:

UNO [17]2 years ago

5 0

Considering the perimeter concept, we have that:

Danielle's mistake is that she did not consider two outside edges, one of length 6x - 4 and the other of length 12x + 3.

The correct perimeter, in feet, is: P = 50x + 27.

<h3>What is the perimeter of a polygon?</h3>

The perimeter of a polygon is given by the sum of all the lengths of the outside edges of the polygon.

For this problem, the outside edges are given as follows:

2 of 6x - 4, due to the isosceles triangle.

2 of 12x + 3, due to the rectangle.

1 of 14x + 13, also due to the rectangle, and only one, because of the other part of the rectangle with the same length is internal to the prism;

Danielle's mistake is that she did not consider two outside edges, one of length 6x - 4 and the other of length 12x + 3. Considering all the edges, the perimeter is given by:

P = 2(6x - 4) + 2(12x + 3) + 14x + 13

P = 12x - 8 + 24x + 6 + 14x + 13

P = 12x + 24x + 14x + 8 + 6 + 13

P = 50x + 27.

More can be learned about the perimeter of a polygon at brainly.com/question/3310006

#SPJ1

You might be interested in

If a baking tray is 700mm by 600mm, how many of 25cm in diameter can fit into the baking tray?

Trava [24]

1cm=10mm
700mm= 70cm
600mm=60cm

70cm:25cm=2,8 - on length only 2 fit into

60cm:25=2,4 - on width only 2 fit into

Two 25cm in diameter fit into the baking tray.

7 0

4 years ago

BRAINLIEST AWARD NO.2

zzz [600]

Answer:

A whole number first term to render as fifth term a value larger than 10000, should be at least 121

Step-by-step explanation:

The formula is given as recursive since it involves the previous number of the sequence, and defined as:

$a_n=a_{n-1}*3+6$

we also know that the first term is 4

Then in this case, the first five terms are:

$a_1=4\\a_2=4*3+6=18\\a_3=18*3+6=60\\a_4=60*3+6=186\\a_5=186*3+6=564\\$

So if we want to find the first term in the case that the fifth one is greater than 10,000 using this recursive formula, now we have to start backwards, and say that the fifth term is "> 10000" and what the fourth one is.

Notice that if you have this definition for the nth term, we can obtain from it, what the previous term is to find the general rule:

$a_n=a_{n-1}*3+6\\a_n-6=a_{n-1}*3\\\frac{a_n-6}{3} = a_{n-1}\\a_{n-1}=\frac{a_n}{3} -2$

So the rule is to subtract 6 from he term, and divide the subtraction by 3. Then working backwards:

$a_5>10000\\\frac{a_5}{3} -2>\frac{10000}{3} -2\\a_4>=\frac{10000}{3} -2\\\frac{a_4}{3} -2>\frac{\frac{10000}{3}-2}{3}-2 =\frac{10000}{9}-\frac{8}{3} \\a_3>\frac{10000}{9}-\frac{8}{3} \\\frac{a_3}{3} -2>\frac{\frac{10000}{9}-\frac{8}{3} }{3} -2=\frac{10000}{27} -\frac{8}{9} -2=\frac{10000}{27} -\frac{26}{9}\\a_2=\frac{10000}{27} -\frac{26}{9}\\\frac{a_2}{3} -2>\frac{\frac{10000}{27} -\frac{26}{9}}{3} -2=\frac{10000}{81} -\frac{80}{27} \\a_1>\frac{10000}{81} -\frac{80}{27}\approx 120.49$

therefore, the starting first term should be at least about 121 to give a fifth term larger than 10,000

8 0

3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago

How do I solve the linear equation of 27=6(x)+4(y) over 20=2(x)+5(y)

larisa86 [58]

8 0

3 years ago

Evaluate the function f(x) = sec(x - pi/2) for x = 0.

Anvisha [2.4K]

$\sec\left(0-\dfrac{\pi}{2}\right)=\sec\left(-\dfrac{\pi}{2}\right)=\dfrac{1}{\cos \left(-\dfrac{\pi}{2}\right)}=\dfrac{1}{0}$

So, the function $f(x)$ for $x=0$ is undefined.

5 0

3 years ago