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Liula [17]
3 years ago
12

The tree diagram below shows all of the possible outcomes for flipping three coins.

Mathematics
2 answers:
Nana76 [90]3 years ago
7 0

Answer:B

Step-by-step explanation: the number of event is 3 event={HHT, HTH,THH }

And the number of sample space is 8

By using 2^n formula our n is 3 2^3 = 8

The probability = 3/8

Hope it helps

Brainliest please

Vanyuwa [196]3 years ago
6 0

Answer:

B

Step-by-step explanation:

In that scenario, you would have one T and two H's, in any order. Looking at the chart, this happens in 3 different scenarios. Since there are a total of 8 possible outcomes, the probability of this happening is 3/8 or answer choice B. Hope this helps!

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Corresponding angles form when a transversal intersects with two parallel lines.
Nadya [2.5K]

Answer: True

When two lines are crossed by another line (which is called the Transversal), the angles in matching corners are called corresponding angles. When the two lines are parallel Corresponding Angles are equal.

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Solve for the portion. Round to hundredths when necessary.<br> What number is 0.4% of 500?
Yuri [45]

Answer:

2

Step-by-step explanation:

0.4%×500=2

Hope it helps!!!

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What is “6 is 8% of ___?”
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Step-by-step explanation:

The answer is 75 percent

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What is the solution to the system of equations?<br> y = x +3<br> X=-2
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Answer: (-2, 11/6)

Step-by-step explanation:

7 0
3 years ago
The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Two random samples from
Vinvika [58]

Answer:

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

df=n_1 +n_2 -2=13+19-2=30  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

Step-by-step explanation:

Data given

\bar X_{1}=810 represent the mean for sample 1  

\bar X_{2}=770 represent the mean for sample 2  

s_{1}=67 represent the sample standard deviation for 1  

s_{2}=56 represent the sample standard deviation for 2  

n_{1}=13 sample size for the group 2  

n_{2}=19 sample size for the group 2  

\alpha=0.05 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for category 1 is higher than the mean for category 2, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=13+19-2=30  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771  

P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{30}>1.771)=0.0434  

Comparing the p value with the significance level \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

4 0
3 years ago
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