Can someone help me find the value of x for the triangle?
1 answer:
You might be interested in
Answer:
width = let width be w
area = 140
length = 2w-6
Area of a rectangle = l*b
⇒ 2w-6*w=140
⇒
Cot θ = -24/7 and cos θ < 0
"cos θ < 0" means cosine is negative
Remember osmething like "ALL students Take Calculus"?
all is positive in quadrant 1
sine/cosecant is positive only in quadrant 2
tangent/cotangent is positive only in quadrant 3
cosine/secant is positive only in quadrant 4
since cot(angent) is the reciprocal of tangent, tangent must also be negative.
tangent is negative in quadrants II and IV
cosine is negative in quadrants II and III
therefore, θ must lie in quadrant II.
remember the tan θ = y / x. it is the y-coordinate divided by the x-coodinate. the y-coordinate would be the height of this 90 degree triangle that forms. the x-coordinate would be the bottom leg of the 90 degree triangle
then cot θ = x / y. therefore, cot θ = -24 / 7 means x = -24 and y = 7. we draw a triangle with these dimensions.
csc θ = r / y = hypotenuse over opposite (when you view the reference angle labeled as the one to base the hypotenuse/oppoiste on) because it is the reciprocal of sine
the hypotenuse can be found w/ pythagorean theorem
hypotenuse = √[(-24)² + 7²] = 25
therefore,
cot θ = 25/7
"cos θ < 0" means cosine is negative
Remember osmething like "ALL students Take Calculus"?
all is positive in quadrant 1
sine/cosecant is positive only in quadrant 2
tangent/cotangent is positive only in quadrant 3
cosine/secant is positive only in quadrant 4
since cot(angent) is the reciprocal of tangent, tangent must also be negative.
tangent is negative in quadrants II and IV
cosine is negative in quadrants II and III
therefore, θ must lie in quadrant II.
remember the tan θ = y / x. it is the y-coordinate divided by the x-coodinate. the y-coordinate would be the height of this 90 degree triangle that forms. the x-coordinate would be the bottom leg of the 90 degree triangle
then cot θ = x / y. therefore, cot θ = -24 / 7 means x = -24 and y = 7. we draw a triangle with these dimensions.
csc θ = r / y = hypotenuse over opposite (when you view the reference angle labeled as the one to base the hypotenuse/oppoiste on) because it is the reciprocal of sine
the hypotenuse can be found w/ pythagorean theorem
hypotenuse = √[(-24)² + 7²] = 25
therefore,
cot θ = 25/7