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andreev551 [17]
3 years ago
6

A car traveled 180 miles and used 6 gallons

Mathematics
2 answers:
Anna [14]3 years ago
8 0

Answer:The answer is 42 gallons.

Step-by-step explanation:

The car traveled 180 miles on 6 gallons of gas, so it got 30 miles per gallon. So divide 1260 by 30 to find the number of gallons needed to go 1260 miles.

kicyunya [14]3 years ago
4 0
42 gallons is the answer
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Given the following expression. 2 1/4 - (-3 2/5) A. Rewrite the expression using addition. B. Evaluate the expression.
prisoha [69]

Answer:

A. 2 1/4 + 3 2/5

B. 113/20

Step-by-step explanation: For A: All you had to do was multiply -1(-3 2/5) and that was going to make your answer positive because the negatives were going to cancel each other out.

For B: First you had to make your fractions improper fractions instead of mixed numbers. And that would make it 9/4 + 17/5. Next, since they don't have the same denominator, you would have had to find the least common multiple of 5 and 4 which is 20. So then how ever many times your denominator went in to 20, that's what you'll multiply your numerator by. 45/20 + 68/20= 113/20

8 0
3 years ago
If Joey had 5,000,000 dollars and spent 28% of the money, how much will he have left?
Mrac [35]

Answer:

3600000

Step-by-step explanation:

5000000*.28 = 1400000

5000000-1400000 = 3600000

5 0
3 years ago
(x – 3)(4x + 2) using the distributive property. Select the answer choice showing the correct distribution
Nataly [62]

The distributive property: a(b + c) = ab + ac

(x - 3)(4x + 2) = (x)(4x + 2) + (-3)(4x + 2)

= (x)(4x) + (x)(2) + (-3)(4x) + (-3)(2) = 4x² + 2x - 12x - 6

<h3>= 4x² - 10x - 6</h3>
5 0
3 years ago
Please help due today
otez555 [7]
The answer is c
12.4 feet by 9.5 feet
4 0
3 years ago
Match each series with the equivalent series written in sigma notation
PIT_PIT [208]

Answer:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

3 + 12 + 48 + 192 + 768

The expression can be written as:

3 \to 3*4^{0 --- 0

12 \to 3 * 4^{1 ---- 1

48 \to 3 * 4^{2 --- 2

192 \to 3 * 4^{3 ---- 3

768 \to 3 * 4^{4 ---- 4

For the nth term, the expression is:

Term = 3 * 4^{n ---- n

So, the summation is:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

Solving (b):

4 + 32 + 256 + 2048 + 16384

The expression can be written as:

4 \to 4 * 8^0 --- 0

32 \to 4 * 8^1 ---- 1

256 \to 4 * 8^2 --- 2

2048 \to 4 * 8^3 ---- 3

16384 \to 4 * 8^4 ---- 4

For the nth term, the expression is:

Term \to 4 * 8^n ---- n

So, the summation is:

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

Solving (c):

2 + 6 + 18 + 54 + 162

The expression can be written as:

2 \to 2 * 3^0 --- 0

6 \to 2 * 3^1 ---- 1

18 \to 2 * 3^2 --- 2

54 \to 2 * 3^3 ---- 3

162 \to 2 * 3^4 ---- 4

For the nth term, the expression is:

Term \to 2 * 3^n ---- n

So, the summation is:

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

Solving (d):

3 + 15 + 75 + 375 + 1875

The expression can be written as:

3 \to 3 * 5^0 --- 0

15 \to 3 * 5^1 ---- 1

75 \to 3 * 5^2 --- 2

375 \to 3 * 5^3 ---- 3

1875 \to 3 * 5^4 ---- 4

For the nth term, the expression is:

Term \to 3 * 5^n ---- n

So, the summation is:

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

5 0
3 years ago
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