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hammer [34]
1 year ago
5

Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,

-4, 6}
Mathematics
1 answer:
xz_007 [3.2K]1 year ago
7 0

The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.

<h3>How to determine the range of a function?</h3>

Given: 12x + 6y = 24

Here x stands for the input and y stands for the output

Replacing y with f(x)

12x + 6f(x) = 24

6f(x) = 24 - 12x

f(x) = (24 - 12x)/6

Domain = {-4, 0, 5}

Put the elements of the domain, one by one, to estimate the range

f(-4) = (24 - 12((-4))/6

= (72)/6 = 12

f(0) = (24 - 12(0)/6

= (24)/6 = 4

f(5) = (24 - 12(5)/6

= (-36)/6 = -6

The range exists {12, 4, -6}

Therefore, the correct answer is option c. {12, 4, -6}.

To learn more about Range, Domain and functions refer to:

brainly.com/question/1942755

#SPJ4

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damaskus [11]

La rueda recorre una distancia de 75.420 metros tras 60 vueltas. (Correct choice: A)

<h3>Cuánta distancia recorre una rueda que da 60 vueltas?</h3>

La rueda se desplaza sobre el suelo mediante un tipo de movimiento conocido como rodadura, en la que la rueda experimenta rotación y traslación, cuyo centro instantáneo de rotación es el punto de contacto entre la rueda y el suelo.

Si no existe deslizamiento de la rueda con respecto al suelo, entonces la distancia recorrida tras una revolución de la rueda (s), en metros, es descrita por la siguiente ecuación:

s = 2π · r         (1)

Donde r es el radio de la rueda, en metros.

Si tenemos que r = 0.20 m, entonces la distancia recorrida es:

s = 2π · (0.20 m)

s ≈ 1.257 m

Asimismo, la distancia recorrida es directamente proporcional al número de revoluciones de la rueda es y la distancia recorrida tras 60 vueltas es determinada por regla de tres simple:

S = 60 vueltas × (1.257 m / 1 vuelta)

S = 75.420 metros

La rueda recorre una distancia de 75.420 metros tras 60 vueltas.

Para aprender más sobre el movimiento de ruedas: brainly.com/question/2862170

#SPJ1

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Step-by-step explanation:

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