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Bond [772]
1 year ago
6

Solve the inequality - 12 > -16. Then graph the solution.

Mathematics
1 answer:
ozzi1 year ago
7 0

Solve the inequality c - 12 > -16.

\begin{gathered} c-12>-16 \\ c-12+12>-16+12 \\ c>-4 \end{gathered}

Plot the solution on the number line.

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He total variance is $35000 f. the total materials variance is $14000 f. the total labor variance is twice the total overhead va
TiliK225 [7]
Assume that the total overhead variance is x
We are given that the total labor variance is twice the total overhead variance. This means that, the total labor variance is 2x

Total variance can be calculated as follows:
Total variance = Total materials variance + Total overhead variance
                          + Total labor variance

We have:
Total variance = $35000
Total materials variance = $14000
Total overhead variance = x
Total labor variance = 2x

Substitute in the equation and solve for x as follows:
35000 = 14000 + x + 2x
35000 - 14000 = 3x
21000 = 3x
x = 21000/3
x = 7000

Based on the above calculations:
Total overhead variance = x = $7000
Total labor variance = 2x = 2*7000 = $14000
4 0
3 years ago
A ball is thrown with a slingshot at a velocity of 110 ft./sec. at an angle 20 degrees above the ground from a height of 4.5 ft.
Leviafan [203]

Answer:

T= 2.35 seconds

Step-by-step explanation:

⇒The question is on the time of flight.

⇒Time of flight is the time taken for a projected object to reach the ground.It depends on the <u>projectile angle</u> and the <u>initial velocity</u> of the projectile

Given;

Initial velocity of ball= 110ft./sec.

The projectile angle= 20°

Acceleration due to gravity, g=32 ft./s²

⇒Formulae for time of fright T= (2×u×sin Ф)/g

Where T=time of fright, u=initial velocity of projectile, Ф=projectile angle and g=acceleration due o gravity.

<u>Substituting values</u>

T= (2×u×sin Ф)/g

T=( 2×110×sin 20°) / 32

T= 2.35 seconds

3 0
3 years ago
Read 2 more answers
Solve |9x | ≦ 81
goldenfox [79]
C is the answer cause 9 is the common factor
8 0
3 years ago
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
How do you write 0.236 in word form
Helen [10]
Two-hundred thirty six thousandths 

Hope this helps!
6 0
3 years ago
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