To find the weight of 1 load of stone, divide 2/3 by 4.
To divide fractions, use keep change flip.
Keep the first fraction the same, change the division sign into a multiplication sign, and flip the second fraction.
I attached the work and answer for this problem. If you have any questions please feel free to ask.
Hope this helps.
Check the picture below.
now, let's recall that running a segment from a midpoint across to a midpoint in a triangle, creates a midsegment, and a midsegment which is parallel to the "base" of the triangle, is always half of that base.
now, noticing the picture on the top-left triangle, we know those points are midpoints, so those in red are midsegments and therefore half the base, to make it short
IC = HE/2 = 7
JB = IC/2 = 3.5
now onto the top-right triangle, which is the same thing just basing itself on its other end
CG = AH/2 = 10
DF = CG/2 = 5
now, let's go to the picture on the bottom-center
we know that DG = 4, and since D and G are midpoints, DG is the midsegment of CEH thus
CH = 2DG = 8
likewise, on the green triangle ACH, the midsegment IB is half of the base CH, we know CH = 8, so IB = 4.
Answer:
x = 2 and y = 
Step-by-step explanation:
To solve this system of equation, we will follow the steps below;
We will use both elimination and substitution method to solve this system of equations
12x−15y=14 ------------------------------------------------------------------------(1)
8x−15y=6 --------------------------------------------------------------------------(2)
subtract equation (2) from equation (1)
(By doing that the y variable will be eliminated)
4x = 8
Divide both-side of the equation by 4
4x/4 = 8/4
x = 2
Substitute x =2 into equation (2) and then solve for y
8x−15y=6
8(2)−15y=6
16 - 15y = 6
subtract 16 from both-side of the equation
16 - 16- 15y = 6-16
-15y = -10
Divide both-side of the equation by -15
-15y/-15 = -10/-15
y = 
x = 2 and y = 
Answer:
90
Step-by-step explanation: 9 + 6 = 15
So, then you would multiply 15 x 6 which equals 90
Answer:
a) 2.188
b) John's rent is not an outlier
c) His rent has to be higher than $1,235 to be an outlier
Step-by-step explanation:
The mean monthly rent of students at Oxnard University is $780 with a standard deviation of $208.
(a) John’s rent is $1,235. What is his standardized z-score?
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = $1235
μ is the population mean = $780
σ is the population standard deviation = $208
Hence,
z = 1235 - 780/208
z = 2.1875
Approximately to 3 decimal place = 2.188
(b) Is John’s rent an outlier?
No it isn't
(c) How high would the rent have to be to qualify as an outlier?
John’s rent would have to be higher than $1235