Answer:
0.459 Tesla
Explanation:
Faraday's law:
Φ= NAB
V = N Δ (BA) /Δt
the change in BA
was: BA = 0 because initially B was zero.
V=IR
IR = N B A /Δt
q / Δt ×R = N B A / Δt
Or: B = q R / NA = 8.87 x 10^-3 × 45.0 / 1850×4.7 x 10^-4 =
= 0.459 Tesla
If the current in a 160 mHmH coil changes steadily from 22.0 AA to 12.0 AA in 370 msms , what is the magnitude of the induced em
1 answer:
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Answer
given,
copper rod length = 50 cm
density of the copper = 8.92 g/cm³
iron rod length = 50 cm
density of iron = 7.86 g/cm³
mass of iron = density × volume
m_i = 7.86 × A × l/2
m_c = 8.96 × A × l/2
taking the intersection of copper and iron rod be starting point cooper side is taken as positive side and iron side length is taken to be -ve side.
center of mass
=
=
=
=
= 0.015793 m
= 1.579 m (+ve)
center of mass shift to cooper because cooper is heavy.