To solve the problem it is necessary to
apply the concept of Load on capacitors.
The charge Q on the plates is proportional
to the potential difference V across the two
plates.
It can be mathematically defined as:
0= CV
Where.
C= Capacitance
V= Voltage
Our values are given as,
C
= 0.60pF
V=30V
Substituting values in the above formula,
we get
Q= CV
Q
= 0.6 * 30
Q
= 18pC
Where
1pC= 10-12Coulomb
Therefore the charge must be 18pC to
Create a 30V pore potential difference
Answer:
a. 2500 cm³.
b. 2.5 litres.
Explanation:
Given the following data:
Density = 0.8g/cm³
Mass = 2000g
To find the volume of the petrol;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
Making volume the subject of formula, we have;
Substituting into the equation, we have:
Volume = 2500 cm³
a. The volume of the petrol in the can in cubic centimeters (cm³) is 2000.
b. The volume of the petrol in the can in litres;
1000 cm³ = 1 litre
2500 cm³ = x litres
Cross-multiplying, we have;
1000x = 2500
x = 2500/1000
x = 2.5 litres.
Therefore, the volume of the petrol in the can in litres is 2.5.
Answer:
gravitational force acting on the piano (piano's weight)
force of Chadwick on the piano
force of the floor on the piano (normal force)
Explanation:
Figure is missing: found it in attachment.
In the figure, we notice that the piano is accelerating along the horizontal direction: this means that there is a net force acting along this direction. This force is prodiced by Chadwick, and it acts in the same direction as the acceleration, so one force is:
force of Chadwick on the piano
Also, every object on Earth experencies the force of gravity, which is also called weight. The weight of the piano acts downward, so a second force is:
gravitational force acting on the piano (piano's weight)
Finally, we notice that the piano is in equilibrium along the vertical direction (no acceleration): this is because there is another force acting opposite to the piano's weight (and with equal magnitude), and this force is the normal force exerted by the floor on the piano:
force of the floor on the piano (normal force)